<span>the Fair Debt </span>Collection Practices Act, also know as the <span>FDCPA
(i know this is probably a little late) sorry :( </span>
The inversion would suppress recombination.
In Drosophila, the mutations which are recessive are lethal or recessive sterile. Balancer chromosomes are used to hold the deleterious mutations in stable shares as well as to save you recombination with the aid of suppressing.
Chromosomal inversions prevent the recuperation of recombinant chromosomes in ways.
- the crossovers do now not shape within the location of inversion breakpoints, due to the fact synapsis is inhibited.
- unmarried crossovers' inner inversions result in aneuploid gametes that cannot give upward push to normal progeny.
Drosophila is a genus of flies, belonging to the own family Drosophilidae, whose participants are often referred to as "small fruit flies" or (much less regularly) pomace flies, vinegar flies, or wine flies, a connection with the feature of many species to linger around overripe or rotting fruit.
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Answer:
Explanation:
Ribosomes are specialized to carry protein synthesis [Manufacture of protein]. Since, Ribosomes are attached to rough endoplasmic reticulum which means that the function of RER is also protein synthesis. If a cell has a very large amount of ribosomes attached to its rough endoplasmic reticulum, Then the cell will probably carry out the manufacture of protein.
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<h2>~AnonymousHelper1807</h2>
Answer:
sorry friend cant help ya here.
Explanation:
im not rlly that smart :/
160g of O₂ will be required to fully react with 150g of glucose when glucose is broken down in our bodies to produce carbon dioxide and water.
The breakdown of glucose in our bodies can be represented by the following reaction:
C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(g)
As shown in the reaction, a mole of glucose reacts with 6 moles of oxygen.
To calculate the molecular mass:
1 mole of glucose (C₆H₁₂O₆) = (6x12) + (12x1) + (6x16) = 180g
6 moles of oxygen= 6x (2x16) = 192g
180g of glucose reacts with 192g of oxygen. So, to calculate the amount of oxygen required to fully react with 150g of glucose=
150 x 192/180 = 160g of oxygen.
Therefore, 160g of oxygen is required to fully react with 150g of glucose.
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