X= 45
so 2x -> 2(45) would be 90
(3/x)+(4/(x^2))
give common denominator:
(3x/(x^2))+(4/(x^2)) = (3x+4)/(x^2)
Answer:
((6x+3)(5x+3))/10
Step-by-step explanation:
Simplify:
=((6x+3)/4)((10x+6)/5)
=((6x+3)(10x+6))/20
=((6x+3)(5x+3))/10
;)
In order to answer you need to keep in mind what is a logarithm:
logb x = n is the equivalent of asking "you should raise the base b <span>to <span>what number n</span></span> in order to get x?": bⁿ = x
From this follows that b must be positive, otherwise the function is not defined everywhere in R: for example, take log(-2) x = 0.5 ? This means:

=√(-2) which is impossible in R.
Therefore, both answers A and C are not correct because they take in consideration negative values.
If we take the base between 0 and 1 excluded, we have a fraction whose denominator is bigger than the numerator. Such a fraction, elevated to increasing exponents get smaller, for example:
(1/2)² = 1/4
(1/2)³ = 1/8
(1/2)⁴ = 1/16
Therefore the function is dereasing and answer B is incorrect.
The right answer is, therefore,
D) b > 1.
So since we are solving for x, put 20 instead of f(x):
20 = 2(x + 4)
You can distribute 2 to x and 4:
20 = 2x + 8
Subtract both sides by 8:
12 = 2x
Divide both sides by 2
6 = x