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2 years ago

Identify the value of 2x degrees and x degrees

Mathematics

1 answer:

natka813 [3]2 years ago

8 0

X= 45
so 2x -> 2(45) would be 90

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Suppose c>d. explain why the following inequalities are true:

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Answer: Optional

Step-by-step explanation:

Since c is greater than d, 2c would be greater than 2d, because when it’s like this 2c

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2 years ago

316.7 gallons to pints

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3 years ago

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The parent function f(x)=log^3x has been transformed by reflecting it over the X axis, stretching it vertically by a factor of t

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2 years ago

Please please please help me

Leviafan [203]

The correct answer is 17 what i did was plug in 17 where ever you see x so x2 would be 17x2 an then plus the 5 gives u 39 3x 17x3=51 51+10=61 now add the totals 61 plus 39 gives u 100

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2 years ago

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Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

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3 years ago