Can someone please help me solve this math problem? Thank you!

Softa [21]

To solve for a variable, you need to get it (x) by itself.

2x² - 4x + 5 = 6 Subtract 6 from both sides
2x² - 4x - 1 = 0 Plug this into the Quadratic Formula

a = 2 , b = -4 , c = -1
x = $\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ Plug in your values
x = $\frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-1)} }{2(2)}$ Simplify
x = $\frac{4 \pm \sqrt{16 + 8} }{4}$ Simplify
x = $\frac{4 \pm 2\sqrt{6} }{4}$ Simplify by removing a 2 from every term
x = $\frac{2 \pm \sqrt{6} }{2}$ Simplify by taking the fraction apart
x = $\frac{2}{2} \pm \frac{ \sqrt{6} }{2}$ Change $\frac{2}{2}$ to 1
x = 1 $\pm \frac{ \sqrt{6} }{2}$ Simplify $\frac{ \sqrt{6} }{2}$ to $\sqrt{ \frac{3}{2} }$
x = 1 $\pm \sqrt{ \frac{3}{2} }$

4 0

3 years ago

An obtuse triangle has two angles 45 n 18 ,and a third unknown angle theta what's the value of the unknown angle

zlopas [31]

Answer:

An obtuse triangle has two angles 45 and 18. The value of the unknown angle is $117^{\circ}$

Solution:

Given that two angles of an obtuse triangle is 45 and 18.

Third angle is θ

We are asked to find the value of third unknown angle theta

According to angle sum property of triangle, sum of three angles of triangle is $180^{\circ}$

This means in our case sum of 45, 18 and θ should be $180^{\circ}$

$\begin{array}{l}{=>45+18+\theta=180} \\ {=>\theta=180-63=117^{\circ}}\end{array}$

Hence value of unknown third angle of an obtuse triangle is $117^{\circ}$

7 0

3 years ago

Most college-bound students take either the SAT(Scholastic Assessment Test) or the ACT (which originally stood for American coll

Jlenok [28]

Answer:

Luis would need to have a SAT score of 574.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Nicole's z-score:

ACT scores have a mean of about 21 with a standard deviation of about 5, which means that $\mu = 21, \sigma = 5$