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VLD [36.1K]
3 years ago
13

Multistep Sandy charges each family that she babysits a flat fee of $10 for the night and an extra $5 per child.kimmi charges $2

5 per night no matter how many children a family has write a equation that compare the two girls also is the fees are the same how many children a family have to have in order to be the same
Mathematics
2 answers:
konstantin123 [22]3 years ago
8 0

Step-by-step explanation:

Consider the provided information.

Sandy charges each family that she babysits a flat fee of $10 for the night and an extra $5 per child.

Let x is the number of child, Sandy charges fixed fee of $10 and $5 for each child. Thus, the charges for one night is:

10+5x

Kimmi charges $25 per night no matter how many children a family has. Thus, the charges for one night is:

25

Now we need to write an equation that would compare the two girls charges:

10+5x=25

Thus, the required equation is 10+5x=25.

Now we need to find how many children a family have in order to be the same charges.

For the same charges solve the equation as shown:

10+5x=25

5x=15

x=3

So, the number of children has to be 3 for same charge.

Llana [10]3 years ago
5 0
N= night c= child
sandy= $10+$5c
kimmi= $25n
if sandy babysits 3 children for one night they will both be the same price
sandy= $10+5(3)=$25
kimmi= $25
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The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a
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Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

<u><em>Let X = time for this event for boys in secondary school</em></u>

SO, X ~ Normal(\mu=460,\sigma^{2} =40^{2})

The z-score probability distribution for normal distribution is given by;

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where, \mu = mean time = 460 seconds

            \sigma = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

<u>Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;</u>

       P(X > x) = 0.10   {where x is the required time which boy need to beat}

       P( \frac{X-\mu}{\sigma} > \frac{x-460}{40} ) = 0.10

        P(Z > \frac{x-460}{40} ) = 0.10

<em>So, the critical value of x in the z table which represents the top 10% of the area is given as 1.2816, that is;</em>

<em>                   </em>      \frac{x-460}{40} =1.2816

                         {x-460}{} =1.2816\times 40

<em>                           </em>x = 460 + 51.264 = <u>511.264 seconds</u>

Hence, the time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

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