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skelet666 [1.2K]
3 years ago
8

A small bulb is rated at 7.5 W when operated at 125 V. The tungsten filament has a temperature coefficient of resistivity α = 0.

0045/°C. When the filament is hot and glowing, its temperature is seven times room temperature (20 °C). What is the resistance of the filament (in ohms) at room temperature? Group of answer choices 1911 1350 1280 5630 4530
Physics
1 answer:
alisha [4.7K]3 years ago
5 0

To solve this problem we will apply the concepts related to resistance as a function of temperature, product of the relationship between the squared voltage and the power. Mathematically this is,

R = \frac{v^2}{P}

Here,

R = Resistance (At function of temperature)

v = Voltage

P = Power

Then we have,

R at 140°C (7 times room temperature),

R(140\°C) = \frac{125^2}{7.5}

R(140\°C) = 2083.33\Omega

The relationship between normal temperature and increased temperature would then be given by,

R(140\°C) = R(20\°C)(1 +\alpha (\Delta T))

R(140\°C) = R(20\°C)(1+(4.5*10^{-3})(140-20))

R(20\°C) = \frac{2083.33}{1.54}

R(20\°C) = 1352.81\Omega

Therefore the correct value of the group of answer is 1350

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A model rocket is launched directly upward at a speed of 16 meters per second from a height of 2 meters. The function f(t)=−4.9t
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Hmax=15.06 meters

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\frac{df}{dt} =0\\\frac{df}{dt} =\frac{d}{dt} (-4.9t^2+16t+2)\\\frac{df}{dt} =-4.9*2t+16\\-9.8t+16=0\\t=16/9.8\\t=1.63 secs

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3 years ago
An object is moving along a straight line, and the uncertainty in its position is 1.90 m.
just olya [345]

Answer:

2.78\times 10^{-35}\ \text{kg m/s}

6.178\times 10^{-34}\ \text{m/s}

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\Delta p = Uncertainty in momentum

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\Delta p\geq m\Delta v\geq 2.78\times 10^{-35}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{m}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{0.045}\\\Rightarrow \Delta v\geq 6.178\times 10^{-34}\ \text{m/s}

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Answer:

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