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riadik2000 [5.3K]
3 years ago
9

Calculate the amount of work done if you use a 100N force to push a 50kg box 5m across the kitchen floor.

Physics
2 answers:
irinina [24]3 years ago
6 0
So if the formula for work is force times displacement times cosine(theta), you'd plug in the numbers

100x5 (since there's no angle in the problem, cosine(theta) isn't used

100x5 = 500

So the answer would be B.

Hope that helps!
Naya [18.7K]3 years ago
3 0
We know, W = F * s
Here, F = 100 N
s = 5 m

Substitute their values, 
W = 100 * 5
W = 500 J

In short, Your Answer would be Option B

Hope this helps!
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 Step by step solution :

standard deviation is given by :

\sigma = \sqrt\dfrac{{\sum (x-\bar{x})^2}}{n}

where, \sigma is standard deviation

\bar{x} is mean of given data

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From the above data, \bar{x}=24.88

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If  x=23.9, then (x-\bar{x})^2=0.9604

if x=26.1, then (x-\bar{x})^2=1.4884

If x=25.1, then (x-\bar{x})^2=0.0484

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so, \sum (x-\bar{x})^2 =\frac{0.0064+0.9604+1.4884+0.0484+0.1444}{5}

\sum (x-\bar{x})^2 =2.648

\sqrt{\sum \frac{(x-\bar{x})^2}{n}}

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3 years ago
You are working out on a rowing machine. Each time you pull the rowing bar (which simulates the oars) toward you, it moves a dis
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