All categories

2 years ago

Calculate the amount of work done if you use a 100N force to push a 50kg box 5m across the kitchen floor.

2 answers:

6 0

So if the formula for work is force times displacement times cosine(theta), you'd plug in the numbers

100x5 (since there's no angle in the problem, cosine(theta) isn't used

100x5 = 500

So the answer would be B.

Hope that helps!

Naya [18.7K]2 years ago

3 0

We know, W = F * s
Here, F = 100 N
s = 5 m

Substitute their values,
W = 100 * 5
W = 500 J

In short, Your Answer would be Option B

Hope this helps!

You might be interested in

Let v1, , vk be vectors, and suppose that a point mass of m1, , mk is located at the tip of each vector. The center of mass for

g100num [7]

Answer:

Explanation:

Center of mass is give as

Xcm = (Σmi•xi) / M

Where i= 1,2,3,4.....

M = m1+m2+m3 +....

x is the position of the mass (x, y)

Now,

Given that,

u1 = (−1, 0, 2) (mass 3 kg),

m1 = 3kg and it position x1 = (-1,0,2)

u2 = (2, 1, −3) (mass 1 kg),

m2 = 1kg and it position x2 = (2,1,-3)

u3 = (0, 4, 3) (mass 2 kg),

m3 = 2kg and it position x3 = (0,4,3)

u4 = (5, 2, 0) (mass 5 kg)

m4 = 5kg and it position x4 = (5,2,0)

Now, applying center of mass formula

Xcm = (Σmi•xi) / M

Xcm = (m1•x1+m2•x2+m3•x3+m4•x4) / (m1+m2+m3+m4)

Xcm = [3(-1, 0, 2) +1(2, 1, -3)+2(0, 4, 3)+ 5(5, 2, 0)]/(3 + 1 + 2 + 5)

Xcm = [(-3, 0, 6)+(2, 1, -3)+(0, 8, 6)+(25, 10, 0)] / 11

Xcm = (-3+2+0+25, 0+1+8+10, 6-3+6+0) / 11

Xcm = (24, 19, 9) / 11

Xcm = (2.2, 1.7, 0.8) m

This is the required center of mass

6 0

3 years ago

Which contains the particles that are vibrating fastest?

Phantasy [73]

Answer:

Boiling water

Explanation:

3 0

2 years ago

An ice cream truck is going 25m/s to the East. It accelerates to 45m/s in the same direction over 5s. What is its acceleration?

Naya [18.7K]

Hello!

We can use the kinematic equation:
$a = \frac{v_f - v_i}{t}$

a = acceleration (m/s²)

vf = final velocity (45 m/s)
vi = initial velocity (25 m/s)

t = time (5 sec)

Plug in the givens:
$a = \frac{45-25}{5} = \frac{20}{5} = \boxed{4 m/s^2}$

6 0

2 years ago

Which force would result in a balanced force for the

ohaa [14]

Answer:

F= 45 N

Explanation:

4 0

2 years ago

1. Driving at slower speeds than traffic flow _____________ .

r-ruslan [8.4K]

The correct option is (D). The strength of electric field depends on the amount of charge that produces the field as well as the distance from the charge.

Further Explanation:

The electric field intensity at a point is the measure of the force exerted by a charge particle on another charge particle in the particular area of its strength.

The electric field intensity at a distance $d$ due to a static charge having charge $q$ is directly proportional to the amount of charge and inversely proportional to the square of the distance between them.

The Electric field intensity due to a charge is given as:

$E = \dfrac{1}{{4\pi {\varepsilon _0}}}\frac{q}{{{r^2}}}$

Here, $E$ is the electric field intensity, $q$ is the amount of charge and $r$ is the distance of the charge from the point.

The above expression of electric field shows that the electric field intensity at a point depends on the amount of charge as well as the distance of the point from the charge.

Thus, the correct option is (D). The strength of electric field depends on the amount of charge that produces the field as well as the distance from the charge.

Learn More:

1. The results of Rutherford’s gold foil experiment demonstrated that thehttps://brainly.com/question/1542931

2. A capacitor with capacitance (c) = 4.50 μf is connected to a 12.0 v batteryhttps://brainly.com/question/8892837

3. A point charge of 7.45 pc is fixed at the originhttps://brainly.com/question/11098511

Answer Details:

Grade: Senior school

Subject: Physics

Chapter: Electrostatics

Keywords: Strength, electric field, charge, distance, electric field intensity, magnitude of charge, electrostatic, test charge, kq/r^2.

7 0

3 years ago

Read 2 more answers