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3 years ago

Calculate the amount of work done if you use a 100N force to push a 50kg box 5m across the kitchen floor.

2 answers:

6 0

So if the formula for work is force times displacement times cosine(theta), you'd plug in the numbers

100x5 (since there's no angle in the problem, cosine(theta) isn't used

100x5 = 500

So the answer would be B.

Hope that helps!

Naya [18.7K]3 years ago

3 0

We know, W = F * s
Here, F = 100 N
s = 5 m

Substitute their values,
W = 100 * 5
W = 500 J

In short, Your Answer would be Option B

Hope this helps!

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When you mix two substances, the heat gained by one substance is equalto the heat lost by the other substance. Suppose you place

Debora [2.8K]

Answer:

A) 8,368 J

B) 0.893 J/gºC

Explanation:

The heat gained by the water can be obtained solving the following equation:

$q_{g} = c_{w} * m * \Delta T (1)$

where cw = specific heat of water = 4.184 J/gºC
m= mass of water = 1,000 g
ΔT = 2ºC
Replacing these values in (1) we get:

$q_{g} = c_{w} * m * \Delta T = 4.184 J/gºC*1,000 g* 2ºC = 8,368 J (2)$

Assuming that the heat energy gained by the water is equal to the one lost by the aluminum, we can use the same equation, taking into account that the energy is lost by the aluminum, so the sign is negative: -8,368 J.
Replacing by the mass of aluminum (125 g), and the change in temperature (-74.95ºC), in (1), we can solve for the specific heat of aluminum, as follows:

$q_{l} = c_{Al} * m_{Al} * \Delta T (3)$

⇒ $-8,368 J = c_{Al}* 125 g * (-74.95ºC) (4)$

$c_{Al} = \frac{-8,368J}{125g*(-74.95ºC} = 0.893 J/gºC (5)$

7 0

3 years ago

Velocity is defined as:

gogolik [260]

Velocity is defined as a change in position.

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3 years ago

How does the intensity of a sound wave change if the distance from the

Alex17521 [72]

Answer:

The new intensity decreases by a factor of 16.

Explanation:

The intensity of sound wave is given by :

$I=\dfrac{P}{A}$

P is power

A is area

$I=\dfrac{P}{4\pi r^2}$

$I\propto \dfrac{1}{r^2}$ , r is distance from the source

If the distance from the source is increased by a factor of 4, r' = 4r

So,

$I'=\dfrac{1}{r'^2}\\\\I'=\dfrac{1}{(4r)^2}\\\\I'=\dfrac{1}{16}\times \dfrac{1}{r^2}\\\\I'=\dfrac{I}{16}$

So, the new intensity decreases by a factor of 16.

8 0

3 years ago

If the half-life of a 2.0 gram sample of a radionuclide is 15 hours, then the half-life of a 1.0 gram sample of the same radionu

Lerok [7]

7.5 hours or 450 minutes. 15/2=7.5

5 0

3 years ago

Which statement is true about a body moving at a constant speed in a circle?

Makovka662 [10]

Answer:

Explanation:

When something is moving at a constant velocity it's called the centripetal force. And the centripetal force accelerates radially outwards. It's like an ambulance siren. the sound waves are being exerted out into the atmosphere radiallly.

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3 years ago