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Sati [7]
3 years ago
11

Each of the four diagrams below represents the orbit of the same comet, but each one shows the comet passing through a different

segment of its orbit around the Sun. During each segment, a line drawn from the Sun to the comet sweeps out a triangular-shaped, shaded area. Assume that all the shaded regions have exactly the same area. Rank the segments of the comet’s orbit from left to right based on the length of time it takes the comet to move from Point 1 to Point 2, from longest to shortest. If you think that two (or more) of the diagrams should be ranked as equal, drag one on top of the other(s) to show this equality.
Physics
1 answer:
Fofino [41]3 years ago
6 0

Answer:

As the areas swept by the comet shown are all equal, the travel time of the comet in each of the presented segments is also the same

Explanation:

Kepler's second law states that an object in orbit round the Sun sweeps an equal area in an equal time interval

Here we have the area swept by the comet in a particular duration of time is constant. That is a comet sweeps equal areas in its orbit around the sun in equal time. Therefore. as the areas swept by the comet shown are all equal, the travel time of the comet in each of the presented segments is also the same.

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Answer:

The final angular velocity is 20rad/s

Explanation:

We are given;

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Thus,

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Now, from work energy theorem,

Work done = Change in kinetic energy

So, W = KE_f - KE_i

Now, Initial Kinetic Energy (KE_i) = 0

Final Kinetic Energy; KE_f = (1/2)Iω²

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Thus,

From, W = KE_f - KE_i, we have;

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Answer:

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