What do control rods do in a nuclear reactor?

A 10-gram aluminum cube absorbs 677 joules when its temperature is increased from 50°c to 125°

kotegsom [21]

Answer : The specific heat of aluminum is, $0.90J/g^oC$

Solution : Given,

Heat absorbs = 677 J

Mass of the substance = 10 g

Final temperature = $125^oC$

Initial temperature = $50^oC$

Formula used :

$Q= m\times c\times \Delta T$

or,

$Q= m\times c\times (T_{final}-T_{initial})$

Q = heat absorbs

m = mass of the substance

c = heat capacity of aluminium

$T_{final}$ = final temperature

$T_{initial}$ = initial temperature

Now put all the given values in the above formula, we get the specific heat of aluminium.

$677g= (10g)\times c\times (125-50)^oC$

$c=0.9026J/g^oC=0.90J/g^oC$

Therefore, the specific heat of aluminum is, $0.90J/g^oC$

7 0

3 years ago

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For a projectile with no air resistance, at the peak of its path, _______________.

3241004551 [841]

Answer: "For a projectile with no air resistance, at the peak of its path, it's velocity is equal to zero"

Explanation:

Suppose that you throw an object up. The initial vertical velocity will be positive, and the acceleration (the gravitational acceleration) will point downwards, meaning that it opposes to the initial direction of the velocity, and that decreases the velocity as the time goes by.

There will be a point where the velocity ( that was positive until now, so until now the height of the object was increasing), is equal to zero, this means that at this moment the object stops moving, and after, because we still have negative acceleration, the velocity will start become negative, and the object will fall down.

Then that point where the velocity was zero is the peak of its path, then we can conclude that:

"For a projectile with no air resistance, at the peak of its path, it's velocity is equal to zero"

4 0

3 years ago

1) A force of 20 Newton acts on a bar having a cross sectional area of 0.8m^2 and length 10cm.calculate the stress developed in

Elanso [62]

Answer:25N/M^2

Explanation:

Force=20N Area=0.8M^2

Stress=force/area

Stress=20/0.8

Stress=25N/M^2

4 0

4 years ago

One average force has a magnitude that is three times as large as that of

valentinak56 [21]

The time interval in which the larger force act is 1.1 seconds.

<h3>What is impulse?</h3>

The impulse produced by an object is determined from the product of force and time of force of the object.

The impulse experienced by an object is the product of mass and velocity of the object or simply the impulse experienced by object is equal to change in the momentum of an object.

J = Ft

where;

F is the applied force
t is the time of force acting

The magnitude of the force that produce impulse of 3 Ns for 3.2 seconds is calculated as;

F = J/t

F = (3 Ns) / (3.2 s)

F = 0.94 N

The magnitude of the force that is three times larger is calculated as;

F₂ = 3 x 0.94 N

F₂ = 2.82 N

The time interval of the larger force is calculated as;

t₂ = J/F₂

t₂ = 3 / 2.82

t₂ = 1.1 seconds

Thus, the impulse experienced by an object is a function of force and time of force action.

Learn more about impulse here: brainly.com/question/25700778

#SPJ1

5 0

1 year ago

A 2.0-mm-diameter copper ball is charged to 40 nC . What fraction of its electrons have been removed? The density of copper is 8

murzikaleks [220]

Answer:

0.02442 × 10⁻⁹

Explanation:

Given:

Diameter of copper ball = 2.00 mm = 0.002 m

Charge on ball = 40 nC = 40 × 10⁻⁹ C

Density of copper = 8900 Kg/m³

Now,

The number of electrons removed, n = $\frac{\textup{Charge on ball}}{\textup{Charge of an electron}}$

also, charge on electron = 1.6 × 10⁻¹⁹ C

Thus,

n = $\frac{40\times10^{-9}}{1.6\times10^{-19}}$

or

n = 25 × 10¹⁰ Electrons

Now,

Mass of copper ball = volume × density

Or

Mass of copper ball = $\frac{4}{3}\pi(\frac{d}{2})^3$ × 8900

or

Mass of copper ball = $\frac{4}{3}\pi(\frac{0.002}{2})^3$ × 8900

or

Mass of copper ball = 0.03726 grams

Also,

molar mass of copper = 63.546 g/mol

Therefore,

Number of mol of copper in 0.03726 grams = $\frac{ 0.03726}{63.546}$

or

Number of mol of copper in 0.03726 grams = 5.86 × 10⁻⁴ mol

and,

1 mol of a substance contains = 6.022 × 10²³ atoms

Therefore,

5.86 × 10⁻⁴ mol of copper contains = 5.86 × 10⁻⁴ × 6.022 × 10²³ atoms.

or

5.86 × 10⁻⁴ mol of copper contains = 35.88 × 10¹⁹ atoms

Now,

A neutral copper atom has 29 electrons.

Therefore,

Number of electrons in ball = 29 × 35.88 × 10¹⁹ = 1023.37 × 10¹⁹ electrons.

Hence,

The fraction of electrons removed = $\frac{25\times10^{10}}{1023.37\times10^{19}}$

or

The fraction of electrons removed = 0.02442 × 10⁻⁹

3 0

3 years ago