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ValentinkaMS [17]
3 years ago
6

In 2005, the total waste generated in a certain country was 4.033 x 10^9 pounds. Also in 2005, the country's population was 2.05

x 10^7. Determine the garbage per capita (per person) in that country in the year 2005
Mathematics
1 answer:
lakkis [162]3 years ago
6 0

Answer:

\frac{Garbage}{People} =\frac{4.033x10^{9} pounds}{2.05 x10^{7} people}

And after operate we got:

196.73 \frac{pounds}{people}

So then the gragbe per capita on this was would be 196.73 \frac{pounds}{people}

Step-by-step explanation:

For this case we know the following info:

Total waste generated for a certain country in 2005 : 4.033x10^9 pounds

Total population for this country in 2005 2.05x10^7 people

And we want to estimate the garbage per capita or per person for 2005, and we can use the following formula:

\frac{Garbage}{People} =\frac{4.033x10^{9} pounds}{2.05 x10^{7} people}

And after operate we got:

196.73 \frac{pounds}{people}

So then the gragbe per capita on this was would be 196.73 \frac{pounds}{people}

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Expressions are polynomials? Select each corect answer
abruzzese [7]

Answer:

  • A: z + 1
  • B: 6 + W
  • D: 2x ^ 4 - y

Step-by-step explanation:

Any expression with terms that have non-negative integer powers of the variables is a polynomial. The cube root of y is not an integer power, so that expression is not part of a polynomial.

The polynomials are listed above.

6 0
4 years ago
Which ordered pair is a solution of the linear system: x+2y=-8 and
andrew-mc [135]

Answer:

option A

A(-2,-3)

Step-by-step explanation:

make y subject of formula

x+2y=-8

2y=-8-x

y=(-8-x)/2

y=-4-x/2

when x=-2

y=-4-(-2)/2

=-4-(-1)

=-4+1

=-3

(-2,-3) is an ordered pair

5 0
3 years ago
In the example we modeled the world population in the second half of the 20th century by the equation P(t) = 2560e^(0.017185t).
Lyrx [107]

Answer: There are 6045 millions world population during the period of 1950 to 2000.

Step-by-step explanation:

Since we have given that

The world population in the second half of the 20 the century by the equation:

P(t)=2560e^{0.017185t}

We need to find the average world population during the period of 1950 to 2000.

So, there are 50 years between 1950 to 2000.

So, t = 50 years.

Therefore, the  average population would be

P(50)=2560e^{0.017185\times 50}\\\\P(50)=6045.15\\\\P(50)\approx 6045\ millions

Hence, there are 6045 millions world population during the period of 1950 to 2000.

4 0
4 years ago
How do you solve this equation ?
nata0808 [166]
The first step to solving this is to solve the equation for x
x = - 21/5 - y
4x + 4y = -14
now,, substitute the given value of x into the equation "4x + 4y = -14"
4( - 21/5 - y) + 4y = -14
next,, solve the equation for y
y∈∅
since this system has no solution for y, your answer is (x,y)∈∅
let me know if you have any further questions
:)
6 0
3 years ago
The monthly demand equation for an electric utility company is estimated to be p equals 59 minus (10 Superscript negative 5 Base
mestny [16]

Answer:

a) The price that maximizes profit is p =$43.

b) The utility shouldn't pass all this increase on the consumers because this would mean a decrease in the profits. They should pass only $7 to consumers price.

Step-by-step explanation:

We have an electric utility company which has a demand function defined by:

p=59-10^{-5}x

where p is the price and x is the the energy in thousands of kWh.

The cost of the company is defined as:

C(x)=3\cdot 10^6+27x

We have to calculate the price that maximizes the utility's profit R(x).

We can define the profit as:

R(x)=p\cdot x-C=(59-10^{-5}x)\cdot x-(3\cdot 10^6+27x)\\\\R(x)=-10^{-5}x^2+(59-27)x-3\cdot10^6\\\\R(x)=-10^{-5}x^2+32x-3\cdot10^6.

To maximize R, we have to derive it and equal to zero

\dfrac{dR}{dx}=0\\\\\\\dfrac{dR}{dx}=-2\cdot10^{-5}x+32=0\\\\\\x=(32/2)\cdot 10^5=16\cdot 10^5=1.6\cdot 10^6

The price that maximizes the profit is then:

p=59-10^{-5}x=59-10^{-5}(16\cdot 10^5)=59-16=43

b) When the unit cost rise from $27 to $41, the utility profit function changes.

We have to calculate the new price that maximizes profit, and then we will know if the rise in cost was transferred to price completely.

The new profit function is:

R(x)=p\cdot x-C=(59-10^{-5}x)\cdot x-(3\cdot 10^6+41x)\\\\R(x)=-10^{-5}x^2+(59-41)x-3\cdot10^6\\\\R(x)=-10^{-5}x^2+18x-3\cdot10^6

To maximize R, we have to derive it and equal to zero

\dfrac{dR}{dx}=0\\\\\\\dfrac{dR}{dx}=-2\cdot10^{-5}x+18=0\\\\\\x=(18/2)\cdot 10^5=9\cdot 10^5

We calculate the new price as:

p=59-10^{-5}x=59-10^{-5}(9\cdot 10^5)=59-9=50

The new price is $7 dollars above the previous maximizing price, so the rise in unit cost is only transferred 50% to the price.

The utility shouldn't pass all this increase on the consumers because this would mean a decrease in the profits. They should pass only $7 to consumers price.

4 0
3 years ago
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