I don't know how to do systems of eliminations

Find the missing term (x^12)^5 x (x^-2)^9 x what =(x^40)^5

Annette [7]

Answer:

$x^{158}$

Step-by-step explanation:

We are given,

$(x^{12} )^{5} \times (x^{-2} )^{9} \times y = (x^{40} )^{5}$ .

It is required to find the value of y.

Now, on simplifying above equation, we get,

$x^{60} \times x^{-18} \times y = x^{200}$

i.e. $x^{42} \times y = x^{200}$

i.e. $y = x^{200} \times x^{-42}$

i.e. $y = x^{158}$

Hence, the missing term is $x^{158}$ .

3 0

3 years ago

Read 2 more answers

Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of <em>t</em> for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0

3 years ago

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books off the edge.

krok68 [10]

Answer:

Josh's book lands first
Ben's lands about 0.648 seconds later

Step-by-step explanation:

Using the given equation for v=60 and s=40, the height of Ben's book is ...

h(t) = -16t² +60t +40

We want to find t when h(t) = 0, so we're looking for the solution to ....

0 = -16t² +60t +40

Using the quadratic formula, we find the positive value of t to be ...

t = (-60 -√(60² -4(-16)(40)))/(2(-16)) = (15 +√385)/8 ≈ 4.3277

__

Similarly, the height of Josh's book is ...

0 = -16t² +48t +40

t = (-48 -√(48² -4(-16)(40)))/(2(-16)) = (12 +√304)/8 ≈ 3.6794

__

The time before Josh's book lands is shorter by ...

4.3277 -3.6794 ≈ 0.6482 . . . . . seconds

Josh's book reaches the ground first, by about 0.648 seconds.

3 0

3 years ago

Milo is a running back on his middle school football team. On his first running play he netted -8 yards, and on his second runni

lidiya [134]

To find average, add up the values given and then divide that number by the amount of values that you added to make the larger number.
For example:
If he ran -8 yards first and -6 yards second and they are asking you to find the average, add -8 and -6. You get -14. If you then divide by 2 because you added 2 numbers together, you end up with -7.

Hope this helps!

6 0

3 years ago

Miss Lewis has $523.50 in her savings account. Her bank pays 5 3/4% if interest. If the interest is computed once per year, how

cluponka [151]

Answer:

Interest She'll make in a year is $30.10125

Step-by-step explanation:

Interest = PRT ÷ 100

Principal = $523.50

Rate = 5³/₄% = 5.75%

Time= 1year

Interest I = (523.50 × 5.75 × 1) ÷ 100 = $30.10125

Interest She'll make in a year is $30.10125

5 0

3 years ago