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brilliants [131]
2 years ago
9

You have a pet hamster and a pet mouse. The hamster weighs 4/16 of a pound. The mouse weighs 1/16 of a pound. How much more does

the hamster weigh than the mouse?
Mathematics
1 answer:
horsena [70]2 years ago
7 0

Answer: the hamster weighs 3/16 more than the hamster

Step-by-step explanation: there is already a common denominator so you just do 4 minus 1 equals 3 therefore you have 3/16

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Emily had 75 buttons. She gave 15 to Jake. What percent of buttons did she give to Jake?
eduard

Answer:

20%

Since Emily gave 15 of her buttons out of 75, it's just 15/75 or 1/5 which is 20

Step-by-step explanation:

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mike says 3/3 of his fraction model is shaded blue. Ryan says 6/6 of the same model is shaded blue . are the two fractions equiv
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Can someone help me find the value of x for the figures given ? Thanks!
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3 years ago
Calculate the missing length for this cylinder
Snezhnost [94]
I assume by the length you mean height so,

\frac{6908}{ \pi * 22^{2} } ≈ <span>4.54.

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3 years ago
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What’s the answer please help
noname [10]

Answer:

\boxed{\text{A. }\math{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \}}}}

Step-by-step explanation:

The open circle means that the point is not included in the solution set, and the arrow pointing left means that all numbers less than -2 are members.

In set-builder notation, each term has a special meaning. The braces enclose the members of the set.

Here's how you translate the notation,

\begin{array}{rcl}\\\left \{ & = & \text{The set of}\\x & = & \text{all x values}\\| & = &\text{such that}\\x & = & x\\\in & = &\text{is a member of}\\\mathbb{R}, & = &\text{all real numbers, and}\\x < -2 & = & \text{x is less than -2}\\\end{array}\\\text{The answer is }\boxed{\textbf{A. }\mathbf{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \} }}}

3 0
3 years ago
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