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3 years ago

Complete the following proof.

Mathematics

2 answers:

Akimi4 [234]3 years ago

8 0

Answer:

Just saying the answer is 100% correct

timofeeve [1]3 years ago

4 0

Statement:

1. RS tangent to Circle A and Circle B at points R and S

2. AR ⊥ RS, BS ⊥ RS

3. AR ║ BS

Reason:

1. Given

2. Radius ⊥ to tangent

3. 2 lines ⊥ to same line are ║

100% Correct

~Hope it helps~ :)

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What is the interquartile range of the data set?

pychu [463]

The interquartile range of the data set is 30.

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3 years ago

Teresa Gonzalez and Alan Carillo spent a total of $215.75 on their prom

agasfer [191]

Answer:$139.88

Step-by-step explanation:

215,75-75.87 is 139.88

4 0

3 years ago

1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.

iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is $53.13\°$

Part 2) The surface area of the pyramid is $288\ cm^{2}$

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

$sin(x)=\frac{16}{20}$

$x=arcsin(\frac{16}{20})=53.13\°$

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

$SA=b^{2}+4[\frac{1}{2}(b)(h)]$

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

$h=b/2$ -------> by an 45° angle

$b=2h$

$sin(45\°)=\frac{h}{6\sqrt{2}}$

$h=6\sqrt{2}(sin(45\°))=6\ cm$

Find the value of b

$b=2(6)=12\ cm$

Find the surface area

$SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}$

3 0

3 years ago

The area of a circular oil slick on the surface of the sea is increasing at a rate of [150m^2/s] how fast is the radius changing

Akimi4 [234]

Answer with Step-by-step explanation:

We are given that

$\frac{dA}{dt}=150m^2/s$

a.Radius =25 m

We have to find rate of change of radius.

We know that

Area of circle, $A=\pi r^2$

Differentiate w.r.t time

$\frac{dA}{dt}=2\pi r\frac{dr}{dt}$

Substitute the values then we get

$150=2\pi (25)\frac{dr}{dt}$

$\frac{dr}{dt}=\frac{150}{50\pi}=\frac{3}{\pi} m/s$

$\frac{dr}{dt}=\frac{3}{\pi} m/s$

b.A= $1000m^2$

Substitute the values then we get

$1000=\pi r^2$

$\pi=3.14$

$r^2=\frac{1000}{3.14}$

$r=\sqrt{\frac{1000}{3.14}}=17.8m$

$\frac{dA}{dr}=2\pi r\frac{dr}{dt}$

Substitute the values then we get

$150=2\pi(17.8)\frac{dr}{dt}$

$\frac{dr}{dt}=\frac{150}{2\pi(17.8)}=\frac{150}{35.6\pi}$ m/s

$\frac{dr}{dt}=\frac{75}{17.8\pi}$ m/s

4 0

3 years ago

How do you solve 2i and 2ii

natta225 [31]

Answer:

15 and 21

Step-by-step explanation:

Given the n th term formula

T = 2n + 5

To find the 5 th and 8 th terms substitute n = 5 and n = 8 into the formula

$T_{5}$ = (2 × 5) + 5 = 10 + 5 = 15

$T_{8}$ = (2 × 8) + 5 = 16 + 5 = 21

5 0

3 years ago

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