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eimsori [14]
3 years ago
6

39. Suppose A is an m n matrix with the property that for all b in Rm the equation Ax D b has at most one solution. Use the defi

nition of linear independence to explain why the columns of A must be linearly independent.
Mathematics
1 answer:
Anna [14]3 years ago
5 0

Answer: trivial solution is the only solution to Ax = 0, therefore columns must be linearly independent.

Step-by-step explanation: Recall that the columns of A are linearly independent if and only Ax = 0 had only the trivial solution. Since Ax = b has at most one solution, therefore the only solution to Ax = 0 is the trivial solution and the column vectors must be linearly independent.

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Solving Exponential Equations (lacking a common base)<br> 31^d=38
Bond [772]

Answer:

d = log 38/log31

d = 1.06

Step-by-step explanation:

31 ^ d = 38

Take log of both sides since the exponential equation have different base (always)

d log 31 = log 38

d = log 38 / log 31

d = 1.58 / 1.491

d = 1.06.

We can actually check to see if this is correct.

Substituting d = 1.06

31^ 1.06 = 38.092

(You see, that's approximately correct)

Keep learning, maths is fun!

8 0
3 years ago
Dave spent 21 minutes completing a race. He walked 9 minutes and jogged the rest. What
nasty-shy [4]
Dave jogged for 9 minuets and walked for 12 minuets
6 0
3 years ago
Why do chairs have legs?
GalinKa [24]

Answer:

cuz they are chairs

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the best jumpshot in 2k20?
torisob [31]

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3 0
3 years ago
a team of 10 players is to be selected from a class of 6 girls and 7 boys. match each scenario to its probability
mars1129 [50]

Step-by-step explanation:

The selection of r objects out of n is done in

many ways.

The total number of selections 10 that we can make from 6+7=13 students is  

thus, the sample space of the experiment is 286

A.  

"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

P(all 6 girls chosen)=35/286=0.12

B.

"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is  

so the probability is 20/286=0.07

C.

"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.  

the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.

"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in  

many ways,

so the probability is 126/286=0.44

Did this help??

8 0
3 years ago
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