620 prime factorization
1 answer:
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Answer:
For a scaler variable, the Gaussian distribution has a probability density function of
p(x |µ, σ² ) = N(x; µ, σ² ) = 1 / 2π×
The term will have a maximum value at the top of the slope of the 1-D Gaussian distribution curve that is when exp(0) =1 or when x = µ
Step-by-step explanation:
Gaussian distributions have similar shape, with the mean controlling the location and the variance controls the dispersion
From the graph of the probability distribution function it is seen that the the peak is the point at which the slope = 0, where µ = 0 and σ² = 1 then solution for the peak = exponential function = 0 or x = µ
Question 1:
For this case we have an equation of the form:
Where,
- <em>k: inverse variation constant. </em>
Then, substituting values we have:
From here, we clear the value of k.
We have then:
Answer:
the constant of inverse variation is:
Question 2:
For this case we have:
Where,
- <em>k: constant of variation. </em>
Then, substituting the value of the constant we have:
We now substitute the value of x:
Answer:
the value of y when x = 4 is: