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professor190 [17]
3 years ago
7

What are all the common factors for 8,16,and 32?

Mathematics
1 answer:
Olenka [21]3 years ago
7 0
1,2,4,8 I might of missed something
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You earn $7.50 per hour at a fast food restaurant. You earned $123.75 last week. How many hours did you work last week?
ladessa [460]
I believe you would need to divide 123.75 by 7.50.

The equation would look something like this:
7.50x=123.75
Where x = # of hours worked
123.75 / 7.50 = 16.5
so x = 16.5
You worked for 16.5 hours
3 0
3 years ago
HURRY plzz Identify to corresponding side to side HG.
a_sh-v [17]

Answer:

it would be EC (B)

Step-by-step explanation:

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3 years ago
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Find the value of x. Write your answer in simplest form.
Brilliant_brown [7]

Answer:

by using Pythagoras theorm

{x}^{2}  +  {x}^{2}  =  {(9 \sqrt{2)} }^{2}  \\ 2 {x}^{2}  = 81 \times 2 \\ 2 {x}^{2}  = 162 \\  {x}^{2}  = 81 \\ x =  \sqrt{81}  \\ x = 9

Step-by-step explanation:

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4 0
3 years ago
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Find . negative square root of 16<br> −4<br> 4<br> ±4<br> −8
Luda [366]

Answer:-4


Step-by-step explanation: the square root is 4, so reverse in to negative, and the answer is -4.


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3 years ago
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Hi, the answer is K but can anyone show why
dlinn [17]

Let's do 51 and 52.

51. The contrapositive has the same truth value as the original statement. That's opposed to the converse, which may or may not be true independent of the original statement.

The contrapositive of IF P THEN Q is IF not Q THEN not P.  They're equivalent.  Here that's If the cat is not female then it is not tricolor.

Answer: C

52.  

(x^3)^{(4-b^2)}=1

x^{3(4-b^2)} = 1

For the statement to be true, the exponent must be zero:

3(4-b^2) = 0

b^2 = 4

b = \pm 2

Both positive 2 and negative 2 have a square of 4.

Answer: K

By the way, usually we assume 0^0=1 so the restriction that x \ne 0 isn't really necessary.  Think of the definition of a polynomial or the binomial expansion:

\displaystyle f(x)=\sum_{k=0}^n a_k x^k

\displaystyle(x+y)^n=\sum_{k=0}^n {n \choose k} x^{k}y^{n-k}

For these common equalities to work when x=0 we need to define 0^0=1


3 0
3 years ago
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