Ask question

Ask question

All categories

3 years ago

10

What is 1 2/4+-3 1/4?

1 answer:

Semmy [17]3 years ago

7 0

The answer is 4 3/4.

You might be interested in

kysen have $0, but he owes his friend $10 for a game. his other friend, James, bought a $6 lunch for him, and kysen said he woul

olya-2409 [2.1K]

Answer:

A $9

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

5 + 11x - 16^2<br><br> What is the answer

lidiya [134]

251+11x that’s the answer

6 0

3 years ago

Read 2 more answers

A lawn sprinkler sprays water 7 feet in every direction as it rotates. What is the distance around the outside circle of water?

Readme [11.4K]

The answer is B. To find the Circumference (what you're looking for) you use 2×pi×radius. Which is 2×pi×7. In terms of pi that's just 2×7, which equals 14. So that means your answer is 14pi.

6 0

3 years ago

Read 2 more answers

Find the total paid on a $65,000 loan with 6% simple interest for 4 years

zubka84 [21]

Answer:

**If the interest is by year then this should work

The interest is $15600 and the amount is $80600.

Step-by-step explanation:

Problem

You deposit $65000 into a bank account paying 6% simple interest per year. You left the money in for 4 years. Find the interest earned and the amount at the end of those 4 years?

Result:

The interest is $15600 and the amount is $80600.

5 0

3 years ago

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

<u>apply chain rule</u>

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$ <u />

<u>maximum volume:</u> <u>when h = 40/3</u>

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

<u>minimum volume:</u> <u>when h = 0</u>

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

2 years ago

Read 2 more answers