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Alona [7]
3 years ago
10

What is 1 2/4+-3 1/4?

Mathematics
1 answer:
Semmy [17]3 years ago
7 0
The answer is 4 3/4.
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792

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What are exponents??????​
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6 0
2 years ago
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
Please help me answer all parts of question 3 in the photo.
Nookie1986 [14]
(i.) CA = πrl
CA = π (5*13)
CA = 65π

(ii.) TA = πrl + πr^2
TA = 65π + π (5^2)
TA = 65π + 25π
TA = 90π

(iii.) To get the height of the cone, you have to use the Pythagorean theorem. Plug in the radius for a and the slant height for c.

a^2 + b^2 = c^2
5^2 + b^2 = 13^2
25 + b^2 = 169 Height = 12
b^2 = 144
b = 12

(iv.) v = (1/3)πr^2h
v = (1/3)π(5^2)*12
v = (1/3)π(25*12)
v = (1/3)π*300
v = 100π


5 0
3 years ago
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