Answer:
We are 95% confident that the average weight of the heaviest egg that is still medium size is 3.52 oz
Step-by-step explanation:
Mean = 3.2 oz, sd = 0.13 oz
Assuming there are 3 heavy eggs, n= 3, degree of freedom = n-1 = 3-1 = 2, t-value corresponding to 2 degrees of freedom and 95% confidence level is 4.303
Error margin = t×sd/√n = 4.303×0.13/√3 = 0.32 oz
Upper limit (heaviest egg that is still medium size) = mean + error margin = 3.2 + 0.32 = 3.52 oz
30 with the remainder of 714
Since the minimum value is 0 and axis of symmetry is -2 this means that the vertex is at -2,0 now with the y intercept of 4. You can now plug the values into Vertex form which will be y=a(x-h)^2+k. a being the shrink or stretch of the parabola, h being the x value of the vertex, and k being the y value of the vertex. with all of that plugged in it should look like y=(x+2)^2. You can check this equation by plugging in 0 as x which should find the y intercept of 4. So it should then look like y=(0+2)^2 -> y=(2)^2 -> y=4
(3p + 6) divided by (79 - 9)
the ratio of the length and width = 3:2
Step-by-step explanation:
let the length be =x
width be = 
area of a rectangle = length X width
so, x X = 384
or, 
X 2/3 = 384
or, = (384 X 3)/2
= 576
or, x = 24 ( taking square root)
hence, length is 24
width is = 24 X (2/3)
=16
so the ratio of length and width = 24 : 16
= 3:2
