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irina [24]
3 years ago
7

Help plzzzz!witch ones are true and witch ones are false

Mathematics
2 answers:
777dan777 [17]3 years ago
8 0
The last one is true I think
fenix001 [56]3 years ago
7 0
T
f
f
and idk about the last one

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I WILL GIVE BRAINLIEST HELP
Anika [276]
There you go it’s not Oscar but it’s the same question

5 0
3 years ago
What is the area of this trapezoid, I WILL GIVE BRAINLIEST TO THE CORRECT ANSWER! URGENT WORTH 90PTS
tresset_1 [31]
192 in.

Hope this helped! ♡
6 0
3 years ago
Read 2 more answers
The question is in the picture
Hoochie [10]
Since you’re dealing with a linear equation in slope-intercept form, we know the equation is going to be in the form of y=mx+b.

Therefore, we need to find the slope (“m”) of the line (change in y/change in x), which is rise/run. We also need to find the y-intercept (“b.”)

1.) (0, -3) (1, -1)
We took two points from the line to find the slope. We will use the 2 coordinate pairs to find the slope.

2.) m=(y2-y1)/(x2-x1)
This is the slope “m” formula.

3.) m=( -1+3)/(1-0)
Input the coordinate values into the formula. The +3 you see is due to -(-3)=+3.

4.) m=2/1
We simplified the above formula.

5.) m=2
By division.

We now have the slope or “m.” M=2. Therefore, the equation rises 2 units and runs 1 unit.

Now, finding the y-intercept:

The y-intercept or “b” is where the line intersects the y-axis. It is the starting point of a linear equation.

To find the y-intercept, we need to figure out what the output is when the input is 0. We can see on the table in the picture that with an input of 0, the output is -3.

Therefore, b=-3. This is because an input of 0 means that there is no movement on the x-axis, so we can determine where the where the linear intercepts the y-axis.

Therefore, the equation is y=2x-3, where m=2 and b=-3.

That’s the answer: y=2x-3
4 0
3 years ago
Hey guys would the domain is all real numbers except 3 and 4 ? Because that’s what I got.
ladessa [460]

Answer:

all reals except 3 & 4

Step-by-step explanation:

recall you cannot have a 0 in the denominator.  

any values of x that would produce a 0 in the denominator are excluded from the domain

factor x^{2} -7x+12    Factors -3, -4

                                  (x-3)(x-4)

x cannot be 3 or 4

8 0
3 years ago
2. If k is a constant, what is the value of k such that the polynomial k2x3 - 6kx+9 is divisible by x - 1?
marysya [2.9K]

Answer: The value of k =3.

Step-by-step explanation:

According to factor theorem, if g(x) =x-a is a factor of p(x) then p(a)=0.

Given: x-1 is a factor of k^2x^3-6kx+9.

then

k^2(1)^3-6k(1)+9=0\\\\\Rightarrow\ k^2-6k+9=0\\\\\Rightarrow\ k^2-3k-3k+9=0\\\\\Rightarrow\ k(k-3)-3(k-3)=0\\\\\Rightarrow\ (k-3)(k-3)=0\\\\\Rightarrow\ k=3

Hence, the value of k =3.

4 0
3 years ago
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