All categories

3 years ago

What is the equation of the line that passes through (4, -1) and (-2, 3)?

Mathematics

1 answer:

timurjin [86]3 years ago

6 0

Answer:

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(3-(-1))/(-2-4)

m=(3+1)/-6

m=4/-6

simplify

m=-2/3

y-y1=m(x-x1)

y-(-1)=-2/3(x-4)

y+1=-2/3(x-4)

y+1=-2/3x+8/3

y=-2/3x+8/3-1

y=-2/3x+8/3-3/3

y=-2/3x+5/3

y-(-2/3x)=5/3

y+2/3x=5/3

2/3x+y=5/3

3(2/3x+y)=3(5/3)

2x+3y=5

2x+3y-5=0

You might be interested in

Can you solve this proof for geometry?

expeople1 [14]

Step-by-step explanation:

please see the proof in the attachment above

8 0

3 years ago

What two numbers multiply to -270 and add up to -3

GrogVix [38]

Answer:

-18 and 15

-18 + 15 = -3

-18 x 15 = -270

6 0

3 years ago

If sec ⁡ θ = − 2 secθ=−2 and the reference angle of θ θ is 6 0 ∘ 60 ∘ , find both angles in degrees from 0 ∘ ≤ θ < 36 0 ∘ 0 ∘

jek_recluse [69]

Yoasuibcerknvsekkvdh

4 0

3 years ago

Answer this maths watch question step-by-step

Scilla [17]

The value of <u>a</u> is 2 and the value of <u>b</u> is 6.

<h3>Factoring</h3>

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization. One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

You should factor the given expression.

$2-\frac{x+3}{x+1}-\frac{x-5}{x-1}\\ \\ 2+\frac{-\left(x+3\right)\left(x-1\right)-\left(x-5\right)\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\\ \\ \mathrm{Apply\:the\:fraction\:rule}:\quad \:a+\frac{b}{c}=\frac{ac+b}{c}\\ \\ \frac{2\left(x+1\right)\left(x-1\right)-\left(x+3\right)\left(x-1\right)-\left(x-5\right)\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\\ \\ \frac{2x+6}{\left(x+1\right)\left(x-1\right)}=\frac{2x+6}{x^2-1}$