What you would do is start crossing the highest and lowest values off on both sides of the chart until you had one or two remaining.
Once that is done, you'll be able to determine the median.
The median in this case is 2.
Hope this helps!

We effectively rewrite the equation as

In order for the LHS to be defined, we need to restrict
, or
. Now, the LHS will vanish when the numerator is 0, which happens for

This value is indeed smaller than 4, so the solution is
.
Answer:
Step-by-step explanation:
In the equation of a straight line (when the equation is written as "y = mx + b"), the slope is the number "m" that is multiplied on the x, and "b" is the y-intercept (that is, the point where the line crosses the vertical y-axis).