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Usimov [2.4K]
3 years ago
11

When they invest K dollars, a fishery can produce Q(K) pounds of fish per month, where Q(K) = 111 K1/3. In t months from now, th

eir total investment will be K(t)=0.5t2+100 t +517 dollars. At what rate is the production of fish changing with respect to time 4 months from now? In 4 months from now, the fisher's production will be

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:

a) The rate of production of fishers per month is changing with time at a rate of 40.5 in 4 months from the start of operations.

b) In 4 months from now, the fisher's production will be 1081.53 pounds of fishes per month.

Step-by-step explanation:

The calculation is presented in the attached images to this solution.

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\huge\text{Hey there!}

\mathsf{23n =2.4}

\large\text{DIVIDE 23 to BOTH SIDES}

\mathsf{\dfrac{23n}{23}=\dfrac{2.4}{23}}

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\large\text{Keep: }\mathsf{\dfrac{2.4}{23}}\large\text{ because it helps us solve for n}

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\mathsd{\dfrac{2.4}{23}= 2.4\div 23\rightarrow \bf 0.104348}

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