When they invest K dollars, a fishery can produce Q(K) pounds of fish per month, where Q(K) = 111 K1/3. In t months from now, th
eir total investment will be K(t)=0.5t2+100 t +517 dollars. At what rate is the production of fish changing with respect to time 4 months from now? In 4 months from now, the fisher's production will be
1 answer:
Answer:
a) The rate of production of fishers per month is changing with time at a rate of 40.5 in 4 months from the start of operations.
b) In 4 months from now, the fisher's production will be 1081.53 pounds of fishes per month.
Step-by-step explanation:
The calculation is presented in the attached images to this solution.
You might be interested in
624/27
first you have to know what number that can be subtracted by 62
1. do 27 times 2 equal 54 then you subtract 62 by 54 equal 8 then you put 84 together that will 84 then multiply 27 times 3 = 81 then subtracted by 84
84-81 equal 3
In the calculator the answer is 23.1111111111
Answer:
Square root of 4 is 2
so 1+=4
frac{[1+sqrt{2x-1]}^2 }{4}=3
so 1+sqrt{2x-1]}^2=12
so 1+sqrt{2x-1}=V12
sqrt{2x-1}=V12-1
2x-1=(V12-1)^2=12-2V12+1=13-2V12
2x=13+1-2V12
2x=14-2V12
x=7-V12
x=7-2V3
I put an attachment to explain better
Step-by-step explanation:
