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Vladimir79 [104]
2 years ago
7

1) (6x2 + 14 - x) + (2x - 2 - 4x2)

Mathematics
1 answer:
lakkis [162]2 years ago
3 0
1 is 1
2 is going to be -8x to the second minus 6 x
3 is 3 plus three x two minus seven x plus two xx 2 minus 6xto the 2
4 is 11
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Which sample has a greater variability, or spread?
avanturin [10]

Answer:

The orange sample

Step-by-step explanation:

The higher the interquartile range the bigger the variance as it the difference between the 0.25 and 0.75 quantiles which basically means if the difference between the 25 percent and 75 percent is higher then there is more variety as they are further away

Would be amazing if you marked brainliest and feel free to comment any follow up questions :)

8 0
3 years ago
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The area of the vegetable garden is 0.4 of the community area of 4.5 x 6.2 . What is the area of the vegetable garden?
Gala2k [10]

Answer:

11.16 units²

Step-by-step explanation:

Area of community area=4.5×6.2= 27.9 units²

Area of vegetable garden=27.9×0.4=11.16 units²

5 0
2 years ago
Which of the segments below is a secant?<br><br> A. XB<br> B. OB<br> C. XV<br> D. XY
s2008m [1.1K]
A secant of a curve is a line that intersects the curve at a minimum of two distinct points.

So the answer is D. XY
5 0
3 years ago
For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?
DaniilM [7]
<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

                        x\neq 1

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]

Now, the determinant of this matrix is:

\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1

Hence,

-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1

4 0
3 years ago
Select all values of w that are solutions to w&lt;5
Mariulka [41]

you want things less than or equal to 5

so A and B

5 0
3 years ago
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