The answer is -7
The arrows both point toward the left side, and sine there are seven spaces the arrows are going through, you subtract 7 spaces and get -7
Hope that helps.
Answer:
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
6
2
−
5
−
4
=
0
6x^{2}-5x-4=0
6x2−5x−4=0
=
6
a={\color{#c92786}{6}}
a=6
=
−
5
b={\color{#e8710a}{-5}}
b=−5
=
−
4
c={\color{#129eaf}{-4}}
c=−4
=
−
(
−
5
)
±
(
−
5
)
2
−
4
⋅
6
(
−
4
)
√
2
⋅
6
Step-by-step explanation:
Answer:
4x + 4
Step-by-step explanation:
F(x) = 2x - 1
G(x) = 3x + 2
H(x) = x²
We have to calculate the expression F(G(x)) - F(x)
F(G(x)) means the composition of functions F(x) and G(x). In order to find F(G(x)) we have to replace ever occurrence of x in F(x) with the value of G(x). So,
F(G(x)) = 2(3x+2) - 1 = 6x + 4 - 1 = 6x + 3
Thus,
F(G(x)) - F(x) = 6x + 3 - (2x - 1)
= 6x + 3 -2x + 1
= 4x + 4
Therefore, the expression F(G(x)) - F(x) equals 4x + 4
This is equal to...
We want "x" so we need to isolate it using laws of exponents...
because 
![x=\sqrt[3]{8^{2}}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B8%5E%7B2%7D%7D)
because ![x^{a/b}=\sqrt[b]{x^{a}}](https://tex.z-dn.net/?f=x%5E%7Ba%2Fb%7D%3D%5Csqrt%5Bb%5D%7Bx%5E%7Ba%7D%7D)
x = 4
answer: B
