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3 years ago

Solve equation by finding square roots. 49x^2 - 16= -7

Mathematics

1 answer:

TEA [102]3 years ago

8 0

Answer:

Solve equation by finding square roots. 49x^2 - 16= -7

49x²-16= -7

49x²= -7 + 16

49x²= 9

find the square root of both sides

7x= 3

x= 3/7

Step-by-step explanation:

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Convert decimal .008 to a fraction

kifflom [539]

It would be 8/1000 as a fraction

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3 years ago

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ValentinkaMS [17]

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3 years ago

Solve.

Serggg [28]

Answer:

The solution is (4, 0)

Step-by-step explanation:

Using Linear combination method to solve:

$2d + e = 8\\d - e = 4\\$

Since "e" have the same coefficient in both equation with opposite operator; we will add.

$(2d + d) + (e - e) = (8 + 4)\\3d = 12\\$

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Since d = 4; put 'd' into any of the equation to get 'e'

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3 years ago

This is precents <br><br> what is 20% of 50

11111nata11111 [884]

The answer is ten hope this helps :-)

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Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

3 years ago