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3 years ago

This is almost the last one

Mathematics

1 answer:

Kamila [148]3 years ago

5 0

The answer is 4 because the portion labelled J shows a constant function but is not at the starting point

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Look at the graph of f(x)=x^2+6x+10. What is the average rate of change between {1,3}?

nydimaria [60]

This equals [f(3) - f(1)] / [3-1]

= 3^2 + 6(3) + 10 - (1^2 + 6(1) + 10) / 2

= (37 - 17) / 2

= 10 Answer

3 0

3 years ago

If four pounds of a certain candy cost $10 how manu pounds of that candy can be purchased for $12

dangina [55]

4.8 pounds, set it up as 4 over ten times x over 12, 4 times 12 divided by ten equals 4.8

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3 years ago

Solve for P in the equation - 15 = p + 2

GarryVolchara [31]

Answer:

p+2=-15 step1:-2 on both sides

p=-17

4 0

2 years ago

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4 cos²x – 1=0<br><br> What is the solution?

andreev551 [17]

Answer:

$x=\frac{\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{5\pi }{3}+2\pi n, n \in \mathbb{Z}$

$x=\frac{2\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{4\pi }{3}+2\pi n, n \in \mathbb{Z}$

$x=\frac{\pi}{3}+\pi n, n \in \mathbb{Z}$

$x=\frac{2\pi }{3}+\pi n, n\in \mathbb{Z}$

Step-by-step explanation:

$4\text{cos}^2(x)-1=0\\4\text{cos}^2(x)=1\\$

$cos(x)=\pm\sqrt{\frac{1}{4} }$

$cos(x)=\pm\frac{1}{2}$

So, when cos(x) is equal to

$\frac{1}{2} \text{ and } -\frac{1}{2}$ ?

For

$cos(x)=\frac{1}{2}$

We are talking about x = 60º and x = 300º, Quadrant I and IV, respectively. In radians:

$x=\frac{\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{5\pi }{3}+2\pi n, n \in \mathbb{Z}$

$x=\frac{\pi}{3}+\pi n, n \in \mathbb{Z}$

For

$cos(x)=-\frac{1}{2}$

We are talking about x = 120º and x = 240º, Quadrant II and III, respectively. In radians:

$x=\frac{2\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{4\pi }{3}+2\pi n, n \in \mathbb{Z}$

$x=\frac{2\pi }{3}+\pi n, n\in \mathbb{Z}$

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3 years ago

What is the square footage of a area 20 feet by 50 feet

Westkost [7]

The footage is 1000 square footage

5 0

3 years ago

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