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2 years ago

Jason borrowed $6,000 at 8% simple interest for 2 years. how much does he pay back? how much interest did he pay?

Mathematics

1 answer:

Step2247 [10]2 years ago

3 0

6000 x 0.08 x 2 = 960

answer: interest $960

hope that helps

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Hey can someone help me ?

morpeh [17]

Sure what do u need help with?

6 0

1 year ago

Y = 5x - 22 y = 4x - 17

Pie

The answer is (5,3). You need to equal both sides out. So 5x-22=4x-17. That will give you x=5. After that you substitute 5 for x in one or both of the equations and get that y=3. Hope this helps!

6 0

2 years ago

Read 2 more answers

Fiind the value of x between 0 and 360 <br>for question 5sin 2x=7cos2x

Degger [83]

Answer:

x=pi*n/2+1/2arctan(7/5)

Step-by-step explanation:

5sin(2x)=7cos(2x)

5tan(2x)=7/5

2x=pi*n+arctan(7/5)

x=pi*n/2+1/2arctan(7/5) for n e Z

6 0

2 years ago

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

7 0

2 years ago

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Please answer this question quickly!

mixer [17]

$40 \times 15 = 600 \div 3 = 200m \: and \: the \: formula \: is \: to \: divide \: and \: multipliction$

6 0

2 years ago