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Musya8 [376]
3 years ago
7

Jason borrowed $6,000 at 8% simple interest for 2 years. how much does he pay back? how much interest did he pay?

Mathematics
1 answer:
Step2247 [10]3 years ago
3 0
6000 x 0.08 x 2 = 960

answer: interest $960

hope that  helps
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Will mark brainliest!!
wlad13 [49]
<span>Solve the system

9x = 27-9y
20x=71-9y

Let's use the "elimination through addition/subtraction method.
Multiply the first equation by -1 so as to obtain +9y:

-9x = -27 + 9y
</span><span>20x=  71-   9y
--------------------

Add these 2 equations together:

</span>-9x = -27 + 9y
20x=  71-   9y
--------------------
<span> 11x = 44

Solve this for x:  x = 44/11 = 4.

Now find y by subst. 4 for x in either of the original equations.

Using the second equation:    </span><span> 

</span>20x=71-9y
20(4) = 71 - 9y
80-71 = -9y
9 = -9y.  Then y = -1.

The solution set is (4,-1).
7 0
3 years ago
F(x)=1256(1.24)^x Identify the initial value.
Mumz [18]

Answer:

1256

Step-by-step explanation:

Given the function F(x)=1256(1.24)^x, the initial value occurs at x = 0

Substitute x = 0 into the function;

F(0)=1256(1.24)^0

f(0) = 1256(1) (any value raise to sero is 1)

f(0) = 1256

hence the initial value is 1256

8 0
3 years ago
What’s the percent of change?<br> Original: 25<br> New: 18
soldier1979 [14.2K]

28% decrease

Solution:

Calculate percentage change

from V1 = 25 to V2 = 18

(V2−V1)|V1|×100

=(18−25)|25|×100

=−725×100

=−0.28×100

=−28%change

=28%decrease

7 0
3 years ago
Can someone explain to me how to do this? I just don't get it.
Maksim231197 [3]

Answer:

x=130

Step-by-step explanation:

triangle=180

180-34-96=50

line=180

180-50=130

7 0
2 years ago
A pan is heated to 393°F, then removed from the heat and allowed to cool in a kitchen where the room temperature is a constant 6
deff fn [24]

Answer:

The approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

Step-by-step explanation:

The formula for D, the difference in temperature between the pan and the room after t minutes is:

D = 324\cdot e^{-0.05t}

Compute the approximate difference in temperature between the pan and the room after 9 minutes as follows:

D = 324\cdot e^{-0.05t}

    =324\times e^{-0.05\times 9}\\\\=206.59

Then the approximate temperature of the pan after it has been away from the heat for 9 minutes is:

D = P - R

206.59 = P - 69

P = 206.59 + 69

P = 275.59°F

Thus, the approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

6 0
3 years ago
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