Question

The surface area of this cylinder to the nearest integer is? (height is 4 in. radius is 6 in.)

Answer 1

Answer:

The surface area is equal to $377\ in^{2}$

Step-by-step explanation:

we know that

The surface area of the cylinder is equal to

$SA=2B+Ph$

where

B is the area of the base of cylinder

P is the circumference of the base of cylinder

h is the height of the cylinder

Find the area of the base B

$B=\pi r^{2}$    

we have

$r=6\ in$

substitute

$B=\pi (6^{2})=36\pi\ in^{2}$

Find the circumference of the base

$P=2\pi r$

we have

$r=6\ in$

substitute

$P=2\pi (6)=12\pi\ in$  

Find the surface area

we have

$B=36\pi\ in^{2}$

$P=12\pi\ in$  

$h=4\ in$

substitute

$SA=2B+Ph$

$SA=2(36\pi)+(12\pi)(4)$

$SA=72\pi+48\pi=120\pi=377\ in^{2}$