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gavmur [86]
3 years ago
15

If you open an account that compounds quarterly in 2020. In what year will it double the starting amount if it has an APR of 3.2

%
Mathematics
1 answer:
Lerok [7]3 years ago
8 0

Answer:

It will double in the year 2063

Step-by-step explanation:

Let the amount deposited be $x, when it doubles, the amount becomes $2x

we can use the compound interest formula to know when this will happen

The compound interest formula is as follows;

A = P(1+r/n)^nt

In this question,

A is the amount which is 2 times the principal and this is $2x

P is called the principal and it is the amount deposited which is $x

r is the interest rate which is 3.2% = 3.2/100 = 0.032

n is the number of times compounding takes place per year which is quarterly which equals to 4

t is the number of years which we want to calculate.

Substituting all these into the equation, we have;

2x = x(1+0.032/4)^4t

divide through by x

2 = (1+ 0.008)^4t

2 = (1.008)^4t

we use logarithm here

Take log of both sides

log 2 = log (1.008)^2t

log 2 = 2t log 1.008

2t = log 2/log 1.008

2t = 86.98

t = 86.98/2

t =43.49 which is 43 years approximately

Thus the year the money will double will be 2020 + 43 years = 2063

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Answer:

Option d

Step-by-step explanation:

Other options are not eligible because

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If the question had been asked as some integers are also, then options b) and c) could have been written . But in this case , it is asked every integer is also.

Thank you!

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Answer:

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

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Step-by-step explanation:

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where D is the discount factor calculated using the formula;

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n=number of periodic payments=payments per year times number of years

⇒In this question you find the discount factor then divide the amount remaining to pay with the discount factor to get monthly payments

Given;

Cost of boat=$32000

Down payment=$14000

Loan to pay=$32000-$14000=$18000

Annual rate=5.5%=i=5.5%÷12=0.458%⇒0.00458

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Finding the discount factor D;

D=\frac{(1+i)^n-1}{i(1+i)^n} \\\\\\D=\frac{(1+0.00458)^{48} -1}{0.00458(1+0.00458)^{48} } \\\\\\D=\frac{1.2455-1}{0.005703} \\\\\\D=\frac{0.2455}{0.005703} =43.05

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Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

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