The –OH+ group is most acidic proton in ln-OH as shown in figure (a). The proton is circled in the figure.
The stabilisation of the conjugate base produced is stabilises due to resonance factor. The possible resonance structures are shown in figure (b).
The acidity of a protonated molecule depends upon the stabilisation of the conjugate base produced upon deprotonation. The conjugate base of ln-OH is shown in figure (a).
The possible resonance structures are shown in figure (b). As the number of resonance structures of the conjugate base increases the stabilisation increases. Here the unstable quinoid (unstable) form get benzenoid (highly stable) form due to the resonance which make the conjugate base highly stabilise.
Thus the most acidic proton is assigned in ln-OH and the stability of the conjugate base is explained.
The level of radioactivity allows them to date fossils and artifacts
4.0 mol. 6.02 x 10. 23 atoms. 3. How many moles are in 2.5g of lithium? 2.5 grams Li. 1 mole. = 0.36 mol. 6.9 g. 4. Find the mass of 4.8moles of iron. 4.8 moles.
Answer:
0.091 mol/L
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity ( unit = mol / L or M )
V = volume of solution in liter ( unit = L ),
n = moles of solute ( unit = mol ),
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the data of the question , it is given that ,
w = 1.5 g
V = 220 mL
Since ,
1 mL = 1/1000L
V = 0.220 L
As we known , the mass of bleach NaOCl is ,
m = 74.44 g/mol
from the above equation , moles can be calculated as -
n = w / m
n = 1.5g / 74.44 g/mol
n = 0.0201 mol
Molarity of the solution is calculated as ,
M = n / V
M = 0.0201 mol / 0.220 L
M = 0.091 mol/L