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soldi70 [24.7K]
3 years ago
13

Some fuel cells are powered by hydrogen. Scientists are looking into the decomposition of water (H2O) to make hydrogen fuel with

the help of the Sun’s energy. What challenge do scientists face with this task.
a Decomposing water requires a high activation energy.
b The Sun isn't a renewable resource.
c Decomposing water results in toxic byproducts.
d cientists are uncertain what to do with the excess oxygen.
Chemistry
1 answer:
skad [1K]3 years ago
5 0

Here we have to choose the challenge which is faced by the scientist to make a hydrogen fuel cell by using water.

The challenge that the scientists are facing a. decomposition of water requires a high energy.

For the generation of fuel cells by hydrogen the use of water (H₂O) is a challenging task as the H-O bond in  water is so strong and need high activation energy.

As per the mechanism of hydrogen fuel cell generation of H₂ is compulsory. Water remains in its solution as H₂O⇔H⁺ + OH⁻. The breaking of hydroxide ion (OH⁻) to form free hydrogen need a high energy, which cannot meet easily by any energy source.

The sun is always a renewable energy source as the energy of sun is infinitive.

The decomposition of water will only produce oxygen (O₂) and hydrogen (H₂) among which H₂ will be used in the fuel cell and O₂ is not at all harmful.

The excess O₂ is always good for the environment as it is the breathing source in the living system.

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3 years ago
The photon of light that is emitted as an electron drops back to its original orbit is:
Alex73 [517]

Answer:

energy

Explanation:

The photon of light that is emitted as an electron drops back to its original orbit is energy and this energy is released during de-excitation process.

The electron is jumped into higher level and back into lower level by absorbing and releasing the energy.

The process is called excitation and de-excitation.

Excitation:

When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits.  For example if electron jumped from K to L it must absorbed the energy which is equal the energy difference of these two level. The excited electron thus move back to lower energy level which is K by releasing the energy because electron can not stay longer in higher energy level and comes to ground state.

De-excitation:

When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum

3 0
3 years ago
Is usually categorized to a specific area in the state known as a soil series
Vikentia [17]

Answer:

Soil series as established by the National Cooperative Soil Survey of the United States Department of Agriculture (USDA) Natural Resources Conservation Service are a level of classification in the USDA Soil Taxonomy classification system hierarchy. The actual object of classification is the so-called soil individual, or pedon.[1] Soil series consist of pedons that are grouped together because of their similar pedogenesis, soil chemistry, and physical properties. More specifically, each series consists of pedons having soil horizons that are similar in soil color, soil texture, soil structure, soil pH, consistence, mineral and chemical composition, and arrangement in the soil profile.[2] These result in soils which perform similarly for land use purposes.

Explanation:

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6 0
3 years ago
Solid potassium chlorate decomposes upon heating to form
olga55 [171]

Answer:

32.6%

Explanation:

Equation of reaction

2KClO₃ (s) → 2KCl (s) + 3O₂ (g)

Molar mass of 2KClO₃ = 245.2 g/mol ( 122.6 × 2)

Molar volume of Oxygen at s.t.p = 22.4L / mol

since the gas was collected over water,

total pressure = pressure of water vapor + pressure of  oxygen gas

0.976 = 0.04184211 atm + pressure of oxygen gas at 30°C

pressure of oxygen = 0.976 - 0.04184211 = 0.9341579 atm = P1

P2 = 1 atm, V1 = 789ml, V2 = unknown, T1 = 303K, T2 = 273k at s.t.p

Using ideal gas equation

\frac{P1V1}{T1} = \frac{P2V2}{T2}

V2 = \frac{P1V1T2}{T1P2}

V2 = 664.1052 ml

245.2   yielded 67.2 molar volume of oxygen

0.66411 will yield = \frac{245.2 * 0.66411}{67.2}  = 2.4232 g

percentage of potassium chlorate in the original mixture = \frac{2.4232 * 100}{7.44} = 32.6%

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3 years ago
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Answer:

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Explanation:

how do I complete this column graph of the number of conduct vs the number of

4 0
3 years ago
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