What is the lateral area of the drawing?

Mathematics

2 answers:

-Dominant- [34]3 years ago

8 0

I think the answer is letter c

Usimov [2.4K]3 years ago

4 0

The correct answer is C.) 22 mi2 because:

In the case of a cube, the lateral surface area consists of the area of four of the cube's sides added together, or 4 times the area of one of the cube's sides. Thus, the lateral surface area of a cube can be found using the formula 4s^2, where s is the side length of the cube.

hope this helps :)

You might be interested in

Tucker bought a new speaker priced at $45 and the sales tax is 7%. What is the total cost of the speaker after tax?

OleMash [197]

The total cost is $41.85

Amount Saved = 45 x 7 / 100
Amount Saved = 315 / 100
Amount Saved = $3.15 (answer).
In other words, a 7% discount for a item with original price of $45 is equal to $3.15 (Amount Saved).
Note that to find the amount saved, just multiply it by the percentage and divide by 100.

3 0

3 years ago

Read 2 more answers

Please answer :( They are fractions and I suck at them.

Ann [662]

Answer:

8/15 (fraction) or 0.5333333333333...

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Sin5A/SinA-cos5A/cosA=4cos2A

irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

$\frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ LHS = \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} \\ \\ = \frac{ \sin5A \:\cos A - \cos5A \: \sin A}{\sin A \:\cos A } \\ \\ = \frac{ \sin(5A -A )}{\sin A \:\cos A} \\ \\ = \frac{ \sin 4A}{\sin A \:\cos A} \\ \\ = \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ =4\cos 2A \\ \\ = RHS \\ \\ thus \\ \\ \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ hence \: proved$