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choli [55]
3 years ago
10

What is the lateral area of the drawing?

Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0
I think the answer is letter c
Usimov [2.4K]3 years ago
4 0
The correct answer is C.) 22 mi2 because:

In the case of a cube<span>, the </span>lateral<span> surface </span>area<span> consists of the </span>area<span> of four of the </span>cube's<span> sides added together, or 4 times the </span>area<span> of one of the </span>cube's<span> sides. Thus, the </span>lateral<span> surface </span>area<span> of a </span>cube<span> can be found using the </span>formula<span> 4s^2, where s is the side length of the </span>cube<span>.
</span>
hope this helps :)
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Which equation represents a line which is perpendicular to the line 2x + y = -5?
Gnesinka [82]

Step-by-step explanation:

Given expression;

   2x + y  = -5;

  The given equation must be written in a form where the slope is the negative inverse of the given one.

A line perpendicular to another will have a negative inverse slope.

   2x + y  = -5

  Equation of a straight line is generally written as;

       y  = mx + c

y and x are the coordinates

m is the slope

c is y - intercept

          2x + y  = -5

                 y  = -2x -5

 The slope of the perpendicular = \frac{1}{2}

So,

the new line;

            y  =  \frac{1}{2}x  -5

Any line with slope of  \frac{1}{2} will be perpendicular

7 0
3 years ago
Where do I put the parentheses in 21-8-6=7
Sliva [168]

Answer:

around 21-8 so the equation would look like this (21-8)-6=7

Step-by-step explanation:

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7 0
3 years ago
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What is the slope of the linear equation 30x-60y=12
crimeas [40]

Answer:

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The slope is 1/2

5 0
3 years ago
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What are the domain and range of this relation? {(3, -9), (11,21), (121,34), (34,1), (23,45)}
Simora [160]

Answer:

domain = ( 3, 11, 121, 34, 23)

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7 0
2 years ago
PLEASe help 30POINTS<br><br> What is the length of segment AB ?
lesya692 [45]

Answer:

\sqrt{74}

Step-by-step explanation:

<u>Distance between two points</u>

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\textsf{let}\:(x_1,y_1)=(2,-6)

\textsf{let}\:(x_2,y_2)=(7,1)

d=\textsf{length of segment AB}

Substituting points into the distance formula and solving for d:

\implies d=\sqrt{(7-2)^2+(1-(-6))^2}

\implies d=\sqrt{5^2+7^2}

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\implies d=\sqrt{74}

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2 years ago
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