In reaction 1 of the Krebs cycle, acetyl‑CoA formed in the pyruvate dehydrogenase reaction condenses with the four‑carbon compound to form <em>citrate </em>with the elimination of coenzyme A. Since the product has three carboxyl groups, this pathway is referred to as the cycle. In reaction 2 of the Krebs cycle, this product then undergoes to form<em> isocitrate. </em>The enzyme is called aconitase because the compound cis‑aconitate is the <em>intermediate product</em> of the reaction. Reaction 3 eliminates CO2 to form the five‑carbon dicarboxylic acid <em>α-cetoglutarate. </em>Oxidation also occurs, with electrons transferred from the substrate to <em>COO-</em> . Consequently, this reaction is an oxidative decarboxylation.
In the image, you can see the reaction 2 in Krebs cycle is a two steps reaction with an intermediate cis-aconitase and a product called isocitrate.
Answer:
Separation method for various ingredients are
1. Paneer from curdled milk. - Filtration
2. Chalk powder from water. - Filtration
3. Sand from salt solution. - Evaporation
4. Saw dust from water. - Skim off, sieve or filter
5. Tea leaves from brew. - Filtration.
Explanation:
By the help of a muslin cloth the paneer is separated from the curdled milk, the process is called as the filtration. The paneer will remain in the cloth and curdled milk will be removed. Separation of chalk powder from water is very easy by the process of filtration, after the filtration the chalk powder retentate and the filtrate obtained is the water in absence of chalk. Salt and sand water separation can be done with the help of evaporation. Separation of the saw dust from water takes place by the method of sieving or sedimentation. The tea leaves are separated from brew by filtration.
Answer:
24.9mL of the stock solution are required
Explanation:
To solve this question we have to find, as first, the moles of HCl that we need to prepare the desire solution. These moles are taken from the stock solution as follows:
<em>Moles diluted solution:</em>
500.0mL = 0.5000L * (0.613mol / L) = 0.3065 moles HCl
As these moles comes from the 12.3M HCl solution, the volume that we need of the stock solution is:
<em>Volume stock solution:</em>
0.3065 moles HCl * (1L / 12.3moles) = 0.0249L 12.3M HCl =
<h3>24.9mL of the stock solution are required</h3>
Yeah it is true buddy boy. Explanation or no?