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3 years ago

Hydrangea is a flower that presents in a variety colors including blue, white and pink. The color of some varieties of

Chemistry

1 answer:

Alika [10]3 years ago

6 0

Answer:

Bigleaf hydrangeas are blue if the pH is between 5.0 and 5.5. The flowers

turn pink when the pH gets around 6.0. The flower color is dependent on

the concentration of aluminum ions (Al+++) in the soil. Aluminum is more

available to the plant when the soil is acidic, less available when the soil is

alkaline.The color of the cultivar called “Endless Summer” of H. macrophylla depends

on soil pH. Red or pink blooms result from neutral or basic soil (pH 7 and

above), whereas blue blooms indicate acidic conditions (pH less than 7).

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What is the ph of a solution of 0.50 m acetic acid?

frosja888 [35]

You need to use the Ka for the acetic acid and the equilibrium equation.

Ka = 1.85 * 10^ -5

Equilibrium reaction: CH3COOH (aq) ---> CH3COO(-) + H(+)

Ka = [CH3COO-][H+] / [CH3COOH]

Molar concentrations at equilibrium

CH3COOH CH3COO- H+

0.50 - x x x

Ka = x*x / (0.50 - x) = x^2 / (0.50 - x)

Given that Ka is << 1 => 0.50 >> x and 0.50 - x ≈ 0.50

=> Ka ≈ x^2 / 0.50

=> x^2 ≈ 0.50 * Ka = 0.50 * 1.85 * 10^ -5 = 0.925 * 10^ - 5 = 9.25 * 10 ^ - 6

=> x = √ [9.25 * 10^ -6] = 3.04 * 10^ -3 ≈ 0.0030

pH = - log [H+] = - log (x) = - log (0.0030) = 2.5

Answer: 2.5

6 0

3 years ago

describe covalent and ionic bonding. include how it works, any key terms and how you can identify each bond ( hard, soft, rigid,

Katena32 [7]

A covalent bond is a bond between 2 non metals, they share electrons. Ionic bonding occurs between a metal and a non-metal, and they transfer electrons.

5 0

3 years ago

Read 2 more answers

At 35°C, K = 1.6 × 10^-5 for the reaction

TEA [102]

Answer:

a) [NOCl] = 0.968 M

[NO] = 0.032M

[Cl²] = 0.016M

b) [NOCl] = 1.992M

[NO] = 0.008 M

[Cl2] = 1.004 M

Explanation:

Step 1: Data given

Temperature = 35°C = 308K

K = 1.6 × 10^-5

Step 2: The reaction

2 NOCl(g) ⇌ 2 NO(g) + Cl2(g)

For 2 moles NOCl we'll have 2 moles NO and 1 mol Cl2

Step 3

a. 2.0 mol pure NOCl in a 2.0 L flask

Concentration at the start:

Concentration = mol / volume

[NOCl] = mol / volume

[NOCl] = 2.0 / 2.0 L

[NOCl] = 1.0 M

[NO] = 0 M

[Cl] = 0M

Concentration at the equillibrium

[NOCl] = 1.0M - 2x

[NO] = 2x

[Cl2]= x

K = [Cl2][NO]² / [NOCl]² = 1.6*10^-5

1.6*10^-5 = ((2x)² * x) / (1.0-2x)²

x = 0.016

[NOCl] = 1.0 - 2*0.016 = 0.968 M

[NO] = 2*0.016 = 0.032M

[Cl²] = 0.016M

b. 2.0 mol NOCl and 1.0 mol Cl2 in a 1.0 L flask

Concentration at the equillibrium

[NOCl] = 2.0 mol / 1.0 L = 2.0 M

[NO] = 0 M

[Cl2]= 1.0 mol / 1.0 L = 1.0 M

Concentration at the equillibrium

[NOCl] = 2.0M - 2x

[NO] = 2x

[Cl2]= 1.0 + x

K = [Cl2][NO]² / [NOCl]² = 1.6*10^-5

1.6 *10^-5 = (2x)²*(1.0+x) / ((2.0-2x)²)

1.6 *10^-5= (2x)² * 1 )/2.0²

1.6 *10^-5= 4x² / 4 = x²

x = $\sqrt{1.6 *10^-5}$ = 4.0*10^-3

[NOCl] = 2.0 - 2*0.004 = 1.992M

[NO] = 2*0.004 = 0.008 M

[Cl2] = 1+ 0.004M = 1.004 M

5 0

3 years ago

A lone pair must reside in which orbital type(s) to participate in resonance/conjugation/delocalization?

tino4ka555 [31]

If a lone pair is participating in resonance, this capability the atom is both Sp2 or Sp hybridized. Looking at the Sp2 case, that ability there are 3 Sp2 orbitals and one P orbital. Assuming there is no formal cost on the atom, the three hybrid orbitals are used for bonding and the lone P-orbital holds the lone pair. Sp3 orbitals are no longer involved with resonance so the lone pair worried in resonance should never be in an Sp3 orbital.

A mathematically described area round a nucleus in an atom or molecule that may also include zero, one, or two electrons Electrons organize themselves in cloudlike areas round the nucleus referred to as orbitals.

Learn more about orbitals here:

brainly.com/question/18914648

#SPJ4

5 0

2 years ago

A small gas cylinder of Helium can be used to fill many more balloons than would fit inside it. Explain how this works, in your

Fudgin [204]

<h2>Gas Molecules Move in Random Motion </h2>

Explanation:

According to the property of an ideal gas the volume occupied by the gas molecules themselves is negligible as compared to the volume occupied by the gas
The molecules of ideal gas obey Newton's laws of motion thus they move in random motion
According to the above statements we can conclude that Helium gas can fill many more balloons as compared to fit the baloons inside the cylinder because the particles of gas is free to move in random motion and can occupy more volume

6 0

3 years ago