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Dimas [21]
3 years ago
13

3\2+t=1\2 help solve for me please

Mathematics
1 answer:
alisha [4.7K]3 years ago
6 0
T=1/3,,,,,,,,,,,,,,,
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Find the value of the expression<br> b + 1 + c + 6<br><br> for b = 4 and c = 9.
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The answer is 20 because you are adding 4 + 1 + 9 + 6= 20
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3 years ago
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How can you write a fraction as a decimal?
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You take the numerator and divide that by the denominator
3 0
3 years ago
16 and 17 please I don’t know if it’s the distance formula
Trava [24]

Answer:

#16 = (0, -10)

#17 = (-18, -3)

Step-by-step explanation:

U wouldn't use the distance formula, you would need to use the Midpoint Formula, which is, M = (x1 + x2 / 2, y1 + y2 / 2). For #16, you plug in (4, -5) for M and 8 for x1 and 0 for y1, so the equation should look like this : (4, -5) = (8 + x2 / 2, 0 + y2 / 2). Then separate the equation to make it easier: 4 = 8 + x2 / 2 and the second equation : -5 = 0 + y2 / 2. So let's do the 1st equation, the first step would be to multiply the 2 to both sides. So the equation should look like this, 8 = 8 + x. Then subtract the 8 from both sides and you get 0 as your x. Now moving on to the 2nd equation, you multiply the 2 to both sides, and you get, -10 = 0 + y, as your equation, but since 0 won't affect it, -10 should be your y. Then just use these steps to solve #17, and your answer should be (-18, -3).

6 0
3 years ago
For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
3 years ago
The Tennessee Titans scored 22 points in week 5 and 35 points in week 6. Find the percent of increase.
Shalnov [3]

Answer:

59.09%

Step-by-step explanation:

35-22=13

13/2= .59090909=59.09%

3 0
2 years ago
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