Heng was trying to factor 10x² + 5x. She found that the greatest common factor of these terms was 5%

Which statements are true about these lines? Select three options.

shepuryov [24]

RS is perpendicular to MN and PQ.

We can use the slopes of these lines to determine the answer.
Slope is given by the formula
m=.

Using the coordinates for M and N, we have:
m=.

Since PQ is parallel to MN, its slope will be as well, since parallel lines have the same slope.

Using the coordinates for points T and V in the slope formula, we have
m=.

This is not parallel to MN or PQ, since the slopes are not the same.
We can also say that it is not perpendicular to these lines; perpendicular lines have slopes that are negative reciprocals (they are opposite signs and are flipped). This is not true of TV either.

Using the coordinates for R and S in the slope formula, we have
m=. Comparing this to the slope of RS, it is flipped and the sign is opposite; they are negative reciprocals, so they are perpendicular.

8 0

3 years ago

Read 2 more answers

The results of a swim Wet are shown. Who swam faster explain your reasoning

kolbaska11 [484]

Answer:

The Susana swam the fastest.

Step-by-step explanation:

Speed : It is defined as the distance traveled per unit time.

Formula used : $Speed = \frac{Distance}{Time}$

First we have to determine speed of the following persons.

For Tawni :

Distance = 50 m

Time = 40.8 s

1.225 m/s which is the speed of Tawni.

--

For Pepita :

Distance = 100 m

Time = 60.2 s

1.661 m/s which is the speed of Pepita

--

For Susana :

Distance = 200 m

Time = 112.4 s

1.779 m/s which is the speed of Susana

From this we conclude that, in this problem meter affects the response and the speed of Susana is more than the Pepita and Tawani.

Thus, Susana swam the fastest.

7 0

2 years ago

what is the polynomial function of lowest degree with leading coefficient of 1 and roots 2 and 1 + square root2

Marta_Voda [28]

If the roots to such a polynomial are 2 and $1+\sqrt2$ , then we can write it as

$(x-2)(x-(1+\sqrt2))$

courtesy of the fundamental theorem of algebra. Now expanding yields

$(x-2)(x-1-\sqrt2)=x^2-2x-(1+\sqrt2)x+2(1+\sqrt2)=x^2-(3+\sqrt2)x+2+2\sqrt2$

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.

So this makes me think you're expected to increase the multiplicity of one of the given roots, or you're expected to pull another root out of thin air. Judging by the choices, I think it's the latter, and that you're somehow supposed to know to use $1-\sqrt2$ as a root. In this case, that would make our polynomial

$(x-2)(x-(1+\sqrt2))(x-(1-\sqrt2))=x^3-4x^2+3x+2$

so that the answer is (probably) the third choice.

Whoever originally wrote this question should reevaluate their word choice...

5 0

2 years ago

Two tenths is equal to what in fractions

SVEN [57.7K]

.2= 2/10
now you have to reduce it and it is 1/5

6 0

3 years ago

Help!!! What is 762.457 X 6.34

MatroZZZ [7]

Hello There
Its pretty tricky but here is your answer
4833.977
Want full answer? here

4833.97738

Good luck brainy

5 0

3 years ago