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Mekhanik [1.2K]
3 years ago
13

Heng was trying to factor 10x² + 5x. She found that the greatest common factor of these terms was 5%

Mathematics
1 answer:
marta [7]3 years ago
4 0

Answer:

2x+1

Step-by-step explanation:

I did the math

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Answer:

9/7is the chance of coming red ball

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What’s the answer??????#9
zzz [600]

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A)

Step-by-step explanation:Quadratics

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Answer correctly please !!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!
valina [46]

Answer:

74º

Step-by-step explanation:

  • Ray TV bisects ∠RTS, so ∠RTV=∠STV=(16x-6)º
  • We also know that ∠RTS=(26x+18)º
  • So, (16x-6)º+(16x-6)º=(26x+18)º
  • We don't need parenthesis, 16x-6+16x-6=26x+18
  • Combine like terms, 32x-12=26x+18
  • Add, 32x=26x+30
  • Subtract, 6x=30
  • Divide, x=5
  • ∠RTV now is [16(5)-6]º=(80-6)º=74º
8 0
3 years ago
10/7=x/5 proportion
LUCKY_DIMON [66]
\boxed{\boxed{\text{ if } \dfrac{a}{b}=\dfrac{c}{d} \text{ then }a\times d=b\times c}}

\dfrac{10}{7}=\dfrac{x}{5}\\\\10\times5=7\times x\\50=7x\\7x=50\\\\\boxed{x=\dfrac{50}{7}}
4 0
3 years ago
Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam
kompoz [17]

For this case, we perform the conversions:

First roll:

1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x

x = \frac {3 * 100} {1}\\x = 300 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71

You can pack 71 boxes.

Second roll:

1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11

You can pack 11 boxes.

Thus, in total you can pack11 + 16 + 71 = 98 \ boxes

Answer:

98 boxes

4 0
3 years ago
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