Answer:
a reflection over the x-axis and then a 90 degree clockwise rotation about the origin
Step-by-step explanation:
Lets suppose triangle JKL has the vertices on the points as follows:
J: (-1,0)
K: (0,0)
L: (0,1)
This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:
J: (0,1) , K: (0,0), L: (1,0)
Then we reflect it across the y-axis and get:
J: (0,1), K:(0,0), L: (-1,0)
Now we go through each answer and look for the one that ends up in the second quadrant;
If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.
If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.
If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.
The third answer is the only one that yields a transformation which leads back to the original position.
Answer:
1 and 17/25
Step-by-step explanation:
First, you make it into a fraction. So because percents are out of 100, it would be 168/100. Then, you take 100 out of it to get a mixed number, 1 and 68/100, and then simplify 68/100 by dividing both sides by the greatest common factor, which is 4. 68/100÷4=17/25. The answer would be 1 and 17/25.
(hope this helps :P)
The answer is 2.99 explanation is that I used my calculator lol
Let's say the cost of student tickets is x and the cost of adult tickets is y. Then:
(1) 12y + 6x = 138
(2) 5y + 11x = 100
If we rearrange equation (1) we get:
12y = 138 - 6x
Now divide each side by 12:
y = 11.5 - 0.5x
We can now substitute this into equation (2):
5(11.5 - 0.5x) + 11x = 100
57.5 - 2.5x + 11x = 100
8.5x = 42.5
x = 5, therefor the cost of a student ticket is $5.00
Answer:
-8/5, 13/5
Step-by-step explanation:
Use the process of elimination to find out the y and plug the y in to get the x.
