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sweet-ann [11.9K]

2 years ago

11

What is the solution to -2|2.2x - 3.3| = -6.6?

1 answer:

sineoko [7]2 years ago

5 0

Answer: x = 0 or x = 3

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Which inequalities is -5 a possible solution?

coldgirl [10]

Answer:

1st, 3rd and second last one

5 0

2 years ago

Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 20 feet,

Harman [31]

First, let's list the lengths of the sides in descending order.

Lengths of sides of quadrilateral ABCD: 20, 18, 14, a

Lengths of sides of quadrilateral EFGH: b, c, 6, 5

From the listings above, we see that he sides measuring 14 and 6 are corresponding.

We are looking for c which corresponds to 18.

14 is to 6 is as 18 is to c

14/6 = 18/c

7/3 = 18/c

7c = 3 * 18

7c = 54

c = 54/7 = 7 5/7

Answer: 7 5/7 feet

5 0

3 years ago

Read 2 more answers

Find the sum: -6 + 3

Andrei [34K]

Negative 6 plus positive 3 equals negative three.

3 0

3 years ago

Read 2 more answers

Find the linear approximation of the function g(x) = 3 1 + x at a = 0. g(x) ≈ Correct: Your answer is correct. Use it to approxi

EleoNora [17]

Answer:

$3.296x+3$

2.835

3.330

Step-by-step explanation:

$g(x) = 3^{1+x}$

Let the linear approximation be L(x) at a = 0. This is given by

$L(x) = g(a) + g'(a)(x-a)$

$g'(x)$ is the derivative of $g(x)$ . To find this, we use the form

If $f(x) = a^x$ , then $f'(x) =a^x\ln a$

By doing this and applying chain rule for the power (which is a function of x), we have

$g'(x) = 3^{1+x}\ln 3$

Then

$g'(0) = 3^{1+0}\ln 3 = 3.296$

Also $g(0) = 3^{1+0} = 3$

Hence $L(x) = 3+(x-0)\times3.296 = 3.296x + 3$

For $3^{0.95}$ , $1+x = 0.95$ and $x=-0.05$

Using this in $L(x)$ ,

$3^{0.95} = 3.296(-0.05) + 3 = 2.835$

For $3^{1.1}$ , $1+x = 1.1$ and $x=0.1$

Using this in $L(x)$ ,

$3^{1.1} = 3.296(0.1) + 3 = 3.330$

7 0

3 years ago

PLEASE LOOK AT PICURE THEN ANWSER, WHOEVER IS CORRECT I WILL MARK BRAINIEST :)

irga5000 [103]

Answer:

b.g(x)= $x^{2}$ +3

Step-by-step explanation:

If two graphs have the same shape and you only want to change one's y intercept, you just have to add or subtract the number at which you want the graph to intercept the y axis from the equation

8 0

3 years ago