Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Then, the answer is 2x^2 + 8x -5
Answer:
Slope = -2
Step-by-step explanation:
slope = (y₂ - y₁)/(x₂ - x₁)
s = (6 - 0)/(-3 - 0)
s = 6 / -3
s = -2
I hope this helped and please mark me as brainliest!
Answer:
i honestly dont know its tooooo hard
Step-by-step explanation:
If (55 + x)/2 is to be 67, then 55+x = 2*67, so x = 2*67 - 55 = 79