Given : Two inequality is given to us . The inequality is v + 8 ≤ -4 and v - 6 ≥ 10 .
To Find : To write those two inequality as a compound inequality with integers .
Solution: First inequality given to us is v + 8 ≤ -4 . So let's simplify it ;
⇒ v + 8 ≤ -4 .
⇒ v ≤ -4 - 8.
⇒ v ≤ -12 .
Now , on simplifying the second inequality ,
⇒ v - 6 ≥ 10 .
⇒ v ≥ 10 + 6.
⇒ v ≥ 16 .
Hence the required answer will be :
First one implies that v is less than or equal to -12 whereas the second one implies that v is greater than or equal to 16 .
Answer:
Step-by-step explanation:
Your answer is 76m.
a^2+b^2=c^2
57^2+b^2=95^2
3249+b^2=9025
b^2=5776
Take sqr on both sides and you get:
b=76m
Answer:
a = (p - 3b)/10
Step-by-step explanation:
Isolate the variable, a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS (Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction).
p = 10a + 3b
First, subtract 3b from both sides.
p (-3b) = 10a + 3b (-3b)
p - 3b = 10a
Next, isolate the a. Divide 10 from both sides.
(p - 3b)/10 = (10a)/10
(p - 3b)/10 = a
a = (p - 3b)/10 is your answer.
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