The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer:
5l.5
Step-by-step explanation: 412 divieded into 8 is 51 or 51.5
H=number of hours
m=total salary
m=15.50h+50
put 400 in for m
400=15.50h+50
now solve for h
400=15.50h+50
-50. -50
350=15.50h
Divide 350 by 15.50to get your final answer
you get a long decimal so I rounded it.
22.6 hours
Yeshgggghhgfgggggggy. B be cc
Answer:
Step-by-step explanation:
- 3 = 
+ 2x ...... <em>(1)</em>
(1) × 12 :
3x - 36 = 4 + 24x
21x = - 40
x = - 
= 
