Answer:
mean= sum of the terms/ (over) number of terms
You need to convert the second equation to slope/intercept form. The first equation is in that form already. Then you can compare slopes.
-6x + 8y = 14
8y = 6x + 14
y = (3/4)x + 14/8
SO THE SLOPE IS 3/4 which is the same as slope of equation 1
Therfore they are parallel.
Answer:
I would reject the null hypothesis because it falls outside of the 95% confidence interval.
Answer:
Option 1: CD is a perpendicular bisector of AB
Step-by-step explanation:
Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.
Formula to find slope

Formula to Find Distance between two points

mAB ( represents , Slope of AB )
1. 
2. 
3. 
4. 
5. 
mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is 



Hence CD ⊥ AB
Also
From Point 4 and point 5 above , we see that
AC = CB
Hence CD bisect AB at C, also CD ⊥ AB
There fore
CD is a perpendicular bisector of AB
Therefor option 1 is true
Answer:
Adding the exponents
Step-by-step explanation:
Multiplying exponential terms with the same base
To multiply exponents with same base , we use exponential property

When we multiply exponents with same base then we add the exponents
So, adding the exponents best explains to simplify the expression that has same base with exponents .