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Bumek [7]
3 years ago
9

Solve the equation if there is no solution, write no solution | m | / 2 - 1 = -3

Mathematics
2 answers:
vitfil [10]3 years ago
8 0
There is no solution

vovangra [49]3 years ago
7 0
There’s no solution to this problem.
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A right cone has a surface area of 440 square inches and a radius of 7 inches. Find its slant height.
EastWind [94]

Answer:

Surface Area of right cone  

               =\pi r(r+\sqrt{h^2 + r^2}

440 = \pi *7*(7+\sqrt{h^2+7^2})\\\\440 = 7\pi (7 + \sqrt{h^2+7^2})\\\\\frac{440}{7\pi } = 7 + \sqrt{h^2+49}\\\\\frac{440}{7\pi } - 7 = \sqrt{h^2+49}\\\\\frac{440-49\pi}{7\pi} =\sqrt{h^2+49}\\\\

\frac{286.062}{21.99} =\sqrt{h^2+49}\\\\13.0087= \sqrt{h^2+49}\\\\(13.0087)^2 = (\sqrt{h^2+49})^2\\\\169.227 = h^2 +49\\\\169.227 - 49 =h^2\\\\120.227 = h^2\\\\h = \sqrt{120.227}  = 10.96in

7 0
3 years ago
What is the answer to this question???
Valentin [98]

Answer:

12/7

Step-by-step explanation:

Make 5 1/7 into improper fraction

(5×7)+1= 36/7

Then make 3 as a fraction

3/1

Divide

36÷3

7÷1

8 0
3 years ago
Find the missing angle
Zanzabum
58 degrees……….:..:………..
3 0
3 years ago
Read 2 more answers
How can you analyze connections between linear equations and use them to solve problems
Alexeev081 [22]

Answer:

Step-by-step explanation:

One of the more obvious "connections" between linear equations is the presence of the same two variables (e. g., x and y) in these equations.

Assuming that your two equations are distinct (neither is merely a multiple of the other), we can use the "elimination by addition and subtraction" method to eliminate one variable, leaving us with an equation in one variable, solve this 1-variable (e. g., in x) equation, and then use the resulting value in the other equation to find the value of the other variable (e. g., y).  By doing this we find a unique solution (a, b) that satisfies both original equations.  Not only that, but also this solution (a, b) will also satisfy both of the original linear equations.

I urge you to think about what you mean by "analyze connections."  

6 0
3 years ago
In your BIO 111 course, you learn that human hair can vary in diameter, but one estimate of the average diameter is 50 microns o
Dafna11 [192]

Answer:

5000 particles of size 10 nanometer should be stacked

Step-by-step explanation:

Average diameter of the of the human hair = 50 micron = 50 × 10⁻⁶ m

Now,

let the number of 10 nanometer i.e 10 × 10⁻⁹ m particle be 'n'

thus,

n × 10 × 10⁻⁹ m = 50 × 10⁻⁶ m

Therefore to find the number of 10 nanometer i.e 10 × 10⁻⁹ m particle,

n = \frac{50\times10^{-6}}{10\times10^{-9}}

or

n = 5000

Hence,

5000 particles of size 10 nanometer should be stacked

4 0
4 years ago
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