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sergeinik [125]
3 years ago
15

Complete the table given rule Rule y=x-4 6 0 4

Mathematics
1 answer:
lakkis [162]3 years ago
6 0

Answer:

answer is 10, 4 and 8

as y = x-4,

6 = x-4

6 + 4 = x

x = 10 for first

similarly,

0= x-4

4+0=x

x= 4 for the second

for the third,

4 = x-4

4+4=x

so x=8

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WILL GIVE BRAINLIEST IF CORRECT ANSWER!!!
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Answer : 2√3

<u>Given </u><u>:</u><u>-</u>

  • A equilateral triangle with side length 4.

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of x in the given figure.

As we know that in a equilateral triangle , perpendicular bisector , angle bisector and median coincide with each other .

  • So the perpendicular drawn in the figure will bisect the given side .
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Now we may use Pythagoras theorem as ,

→ AB² = BC² + AC²

→ 4² = 2² + x²

→ 16 = 4 + x²

→ x² = 16-4

→ x² = 12

→ x =√12 = √{ 3 * 2²}

→ x = 2√3

<u>Hence </u><u>the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>2</u><u>√</u><u>3</u><u> </u><u>.</u>

I hope this helps.

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2 years ago
V70<br><br><br><br><br><br> Estimate the square root of the number below to the nearest tenth
Fiesta28 [93]
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2 years ago
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Do you prefer to express solutions to inequalities using interval notation or as an inequality ? Do you think it’s important to
docker41 [41]

Answer:

I prefer to express solutions to inequalities using interval notation. Both formats are are important but I think interval notation is easier to understand and represents better the solutions.

For example, if you have the following inequation:

x-2> 1

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3 years ago
Tamara is planting bushes around her house. So far today she has planted 5 bushes and she wants to plant at least 12 bushes toda
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Answer:

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3 years ago
Simplify: log base 3 (1/3) ...?
yarga [219]
The answer is 1.

log_3( \frac{1}{3} )
_____
Since log_y(x) =  \frac{log_{10}(x)}{log_{10}(y)}, then: log_3( \frac{1}{3} )= \frac{log_{10} ( \frac{1}{3}) }{log_{10}(3)}
_____
Since \frac{1}{x} = x^{-1}, then: \frac{log_{10} ( \frac{1}{3}) }{log_{10}(3)} = \frac{log_{10}(3^{-1} )}{log_{10}(3)}
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Since log x^{a} =a*logx, then: \frac{log_{10}(3^{-1} )}{log_{10}(3)}= \frac{-1*log_{10}(3)}{log_{10}(3)}

From here: \frac{-1*log_{10}(3)}{log_{10}(3)}=-1*\frac{log_{10}(3)}{log_{10}(3)}=-1*1 = -1

6 0
3 years ago
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