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3 years ago

Which of the following are like terms?

Mathematics

2 answers:

vladimir2022 [97]3 years ago

8 0

The 1, 2, 3 I’m not sure bout the 4th one

kolezko [41]3 years ago

3 0

Dde dwsadqddwwxqwrffrfrfrg4d

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Solve the compound inequality 5 5 x + 2 < 11.

kvv77 [185]

Answer:

x < 9/55

Step-by-step explanation:

55x+2 is less than 11

we subtract 2 from both sides, then we divide both sides by 55.

x is less than 9/55

8 0

3 years ago

Which graph represents 2x <br> - 5 < 15

Nataliya [291]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$2x-5 < 15$

Solve for the inequality

Adds 5 both sides

$2x < 15+5$

$2x < 20$

Divide by 2 both sides

$x < 20/2$

$x < 10$

The solution is the interval ------> (-∞,10)

All real numbers less than 10

In a number line , the solution is the shaded area at left of x=10 (open circle)

The graph in the attached figure

4 0

4 years ago

- 3 ( x + 4 ) = - 24

Slav-nsk [51]

Let's solve your equation step-by-step.

−3(x+4)=−24

Answer:

x=4

7 0

3 years ago

Read 2 more answers

Simplify -2 1/9 - (-4 1/9)

ZanzabumX [31]

Answer:

Step-by-step explanation:

The easiest thing is to convert it to an improper fraction.

-2 1/9 turns into -19/9. -4 1/9 turns into -37/9.

-19/9 - (-37/9) here you would add because you are subtracting a negative number.

-19/9 + 37/9 change it to positive and then add.

-19+37=18

it was 18/9. that simplified is 2.

4 0

3 years ago

Solve the equation 3^(2x) -4*3^(x+1) + 27 = 0. use rules of exponents to change 3^(x+1)

Leviafan [203]

Answer:

$\huge\boxed{x=1\ \vee\ x=2}$

Step-by-step explanation:

$3^{2x}-4\cdot3^{x+1}+27=0\\\\\text{use}\ (a^n)^m=a^{nm}\ \text{and}\ a^n\cdot a^m=a^{n+m}\\\\\left(3^x\right)^2-4\cdot3^x\cdot3^1+27=0\\\\\left(3^x\right)^2-12\cdot3^x+27=0\\\\\text{substitute}\ 3^x=t>0\\\\t^2-12t+27=0\\\\t^2-3t-9t+27=0\\\\t(t-3)-9(t-3)=0\\\\(t-3)(t-9)+0\iff t-3=0\ \vee\ t-9=0\\\\t-3=0\qquad\text{add 3 to both sides}\\\boxed{t=3}\\\\t-9=0\qquad\text{add 9 to both sides}\\\boxed{t=9}$

$\text{We return to substitution:}\\\\3^x=t\\\\3^x=3\ \vee\ 3^x=9\\\\3^x=3^1\ \vee\ 3^x=3^2\\\\\boxed{x=1}\ \vee\ \boxed{x=2}$

4 0

3 years ago