We have a right triangle with
a = one leg = 28
b = other leg = 21
c = hypotenuse = 5x
use the pythagorean theorem (a^2+b^2 = c^2) and solve for x
a^2+b^2 = c^2
28^2+21^2 = (5x)^2
784+441 = 25x^2
1225 = 25x^2
25x^2 = 1225
(25x^2)/25 = 1225/25
x^2 = 49
sqrt(x^2) = sqrt(49)
|x| = 7
x = 7 or x = -7
Since the hypotenuse has length 5x meters, this means
5x = 5*7 = 35
or
5x = 5(-7) = -35
Toss out the negative length as it makes no sense.
The only value of x is x = 7
Therefore the final answer is x = 7
Plug -6 in for x and solve.
y = (-1/3)(-6) + 5
y = 2 + 5
y = 7
Answer:
a.) (x-3)(x-3) = 25 + (x-4)(x-4)
x^2 - 6x + 9 = 25 + x^2 - 8x + 16
-6x + 9 = -8x + 41
2x + 9 = 41
2x = 32
x = 16
b.) 16 - 4 = 12
AB = 12
c.) 16 - 3 = 13
AC = 13
[btw I don't know if this is the method your teacher wants as it does not use the similar triangle :/ but it is still correct :) so good luck bro]
Answer: C
Step-by-step explanation:
