The geometric rule for the nth term of the geometric sequence for which a1 =−6 and a5=−486 is -6 × 3^(n - 1)
<h3>The nth term of a geometric sequence</h3>
First term, a1 = -6
Fifth term, a5 = -486
a5 = ar^(n - 1)
-486 = -6 × r^(5-1)
-486 = -6r⁴
r⁴ = -486 / 6
r⁴ = 81
r = 4√81
r = 3
Geometric rule:
nth term = ar^(n-1)
nth term = -6 × 3^(n - 1)
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<h3>
Answer: 7.20</h3>
Work Shown:
18% = 18/100 = 0.18
18% of 40 = 0.18*40 = 7.20
Answer:
an = -4 * (-3)^ (n-1)
513560652
Step-by-step explanation:
We can find the common ratio
12/-4 = -3
r =-3
The explicit formula is
an =a1 r^(n-1)
an = -4 * (-3)^ (n-1)
We want the 18 th term
a 18 = -4 (-3) ^ 17
513560652
Answer:
the least common multiple is 3
x
(
x
−
2
)
Step-by-step explanation:
Answer:
1/2(2x-6)= -6
Step-by-step explanation:
Multiply the two sides by the equation 2
2x-6=12
move the constant to the right hand side change sign
2x = -12 + 6
calculate the sum
2x= -6
Divide the 2 sides by 2
x= -3
