12x^4-4x/ 4
3x^4-x
X(3x^3-1)
Hope it’s help you
f(x)= -x^2 + x^-1
f(-2)= - (-2)^2 + (-2)^-1 = -4 - 1/2 = -9/2
f(-1)= - (-1)^2 + (-1)^-1 = -1 -1 = -2
f(1) = - (1)^2 + (1)^-1 = -1 +1 = 0
The range is { -9/2, -2, 0}
<span>The best and most correct answer among the choices provided by the question is the third choice:
table 3:
step 1.x^2+8x+15+1=0+1
step 2.x^2+8x+16=1
<span>step 3.(x+4)^2=1</span>
I hope my answer has come to your help. God bless and have a nice day ahead!</span>
