Statements

g If a hypothesis test with a significance level of α rejects H0: μ1=μ2 in favor of Ha: μ1≠μ2, then thecorresponding (1- α)% con

Effectus [21]

Answer:

The statement, (1- α)% confidence interval for (μ₁ - μ₂) does not contain zero is TRUE.

Step-by-step explanation:

The hypothesis for a test is defined as follows:

H₀: μ₁ = μ₂ vs. Hₐ: μ₁ ≠ μ₂

It is provided that the test was rejected st the significance level α%.

If a decision is to made using the confidence interval the conditions are:

If the null hypothesis value is not included in the (1 - α)% confidence interval then the null hypothesis will be rejected and vice versa.

In this case the null hypothesis value is:

H₀: μ₁ - μ₂ = 0.

If the value 0 is not included in the (1 - α)% confidence interval for the difference between two means, then the null hypothesis will be rejected.

Thus the statement, (1- α)% confidence interval for (μ1- μ2) does not contain zero is TRUE.

5 0

3 years ago

Someone please helppp ! i’ll give brainliest to the right answer !

Nuetrik [128]

Answer:

The function is 2 I believe

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can anyone help me with math , its a test.

Solnce55 [7]

Yea I can help:)! What is it???

4 0

3 years ago

Read 2 more answers

How many flowers, spaced every 6 in., are needed to surround a circular garden with a 100-ft radius?

Bond [772]

Answer:

Number of flowers required = 1256

Step-by-step explanation:

Circumference of a circle is given by the formula,

Circumference = 2πr

Here, r = radius of the circle

For a circle with radius = 100 in.

Therefore, circumference = 2π(100)

= 200π

= 628.32 ft

Distance between each flower = 6 in

≈ $\frac{6}{12}$

= 0.5 ft

Number of flowers = $\frac{\text{Circumference}}{\text{Space between each flower}}$

= $\frac{628.32}{0.5}$

= 1256.63

≈ 1256

Therefore, number of flowers required = 1256

4 0

3 years ago

For a standardized psychology examination intended for psychology majors, the historical data show that scores have a mean of 50

Volgvan

Answer:

$P(\bar X>530)=1-0.808=0.192$

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the scores, and for this case we know the distribution for X is given by:

$X \sim N(\mu=505,\sigma=170)$