Answer:
Step-by-step explanation:
Comment
If two secants intersect outside a circle (as these two do) then the angle at which they meet is 1/2 the difference between the intersected arcs. Put much simpler <DCF = 1/2 (arc EG - arc DF)
Givens
Arc EG = 127
Arc DF = 49
Solution
<DCF = 1/2(127 - 49)
<DCF = 1/2(78)
<DCF = 39
The answer to your question is 10 2/5
Answer:
10.17 seconds
Step-by-step explanation:
substitute y=0 into the equation
0=-16x²+153x+98
then use the quadratic formula
a = -16
b= 153
c = 98
Substituting values into the Quadratic equation, you get (Round the values to the nearest hundreth):
x₁= 10.17
x₂= -0.60
Answer:
a
Step-by-step explanation:
![\sqrt[4]{144a^{12}b^{3}} = \sqrt[4]{4^{2}*3^{2}a^{12}b^{3}}=\\= \sqrt[4]{2^{4}*3^{2}a^{12}b^{3}}=2a^{3}\sqrt[4]{3^{2}b^{3}} =\\}=2a^{3}\sqrt[4]{9b^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B144a%5E%7B12%7Db%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B4%5D%7B4%5E%7B2%7D%2A3%5E%7B2%7Da%5E%7B12%7Db%5E%7B3%7D%7D%3D%5C%5C%3D%20%5Csqrt%5B4%5D%7B2%5E%7B4%7D%2A3%5E%7B2%7Da%5E%7B12%7Db%5E%7B3%7D%7D%3D2a%5E%7B3%7D%5Csqrt%5B4%5D%7B3%5E%7B2%7Db%5E%7B3%7D%7D%20%3D%5C%5C%7D%3D2a%5E%7B3%7D%5Csqrt%5B4%5D%7B9b%5E%7B3%7D%7D)
