Question

Write an equation in slope intercept form for the line with slope negative three fourths and y intercept of negative one

Answer 1

The slope intercept form is $y=-\frac{-3x}{4}-1$.

Solution:

Given data: slope = $-\frac{3}{4}$ and y-intercept = –1

y-intercept means (x, y) = (0, –1)

Equation of a line for slope intercept form: $y-y_1=m(x-x_1)$

Here, $x_1=0, y_1=-1$ and $m=-\frac{3}{4}$.

⇒ $y-(-1)=\frac{-3}{4} (x-0)$

⇒ $y+1=\frac{-3}{4} (x)$

Do cross multiplication.

⇒ $4(y+1)=-3x$

⇒ $4y+4=-3x$

⇒ $4y=-3x-4$

Divide both sides of the equation by 4.

⇒ $y=-\frac{-3x}{4}-\frac{4}{4}$

⇒ $y=-\frac{-3x}{4}-1$

Hence the slope intercept form is $y=-\frac{-3x}{4}-1$.