All categories

2 years ago

what are the missing variables?

Mathematics

2 answers:

Vesnalui [34]2 years ago

8 0

Check the picture below.

Julli [10]2 years ago

4 0

Answer:Missing data (or missing values) is defined as the data value that is not stored for a variable in the observation of interest. The problem of missing data is relatively common in almost all research and can have a significant effect on the conclusions that can be drawn from the data [1].

You might be interested in

`h(t)=-5t^{2}+10t+3`

Ipatiy [6.2K]

Solve the equation for
t
t
by finding
a
a
,
b
b
, and
c
c
of the quadratic then applying the quadratic formula.
t
=
10
−
h
+
√
h
2
−
20
h
+
160
10
t
=
10
-
h
+
h
2
-
20
h
+
160
10
t
=
10
−
h
−
√
h
2
−
20
h
+
160
10

8 0

2 years ago

Daisies phone calls for an ask her to meet at the park in exactly 40 minutes which method should daisy use to most accurately de

NeX [460]

She should keep in mind the time the call was placed

8 0

2 years ago

Read 2 more answers

Find the standard deviation of 21, 31, 26, 24, 28, 26

Vesnalui [34]

Given the dataset

$x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}$

We start by computing the average:

$\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26$

We compute the difference bewteen each element and the average:

$x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}$

We square those differences:

$(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}$

And take the average of those squared differences: we sum them

$\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69$

And we divide by the number of elements:

$\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5$

Finally, we take the square root of this quantity and we have the standard deviation:

$\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39$

8 0

3 years ago

Given that (-8,- 7) in on the graph of f(x), find the corresponding point for the fuction f(x -4)

kiruha [24]

The point (x1,y1) on the graph of f(x) is the point (x1-a,y1) for the function
f(x+a)

(-8,-7)=(x1,y1)→x1=-8, y1=-7
f(x-4)=f(x+a)→a=-4

(x1-a, y1)=(-8-(-4), -7)=(-8+4, -7)=(-4,-7)

<span>The corresponding point for the fuction f(x -4) is (-4,-7)</span>

8 0

2 years ago

Solve this problem using substitution

Sergeeva-Olga [200]

Solving for (x,y)
(x-y=8)
(x=y-8) & (y=x-8)

solving for (y,x)
(2y=2x-16)
(y=x-8)&(x=y+8)

6 0

2 years ago

￼what are the missing variables?

what are the missing variables?